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3 years ago

Doreen bought 2 liters of lemonade. How many millimeters of lemonade did Doreen buy?

Mathematics

2 answers:

MatroZZZ [7]3 years ago

7 0

Answer:

Mr. Perkins changed the oil in his car. He bought. 6 liters of oil. He put 4,500 ml in his car.

Step-by-step explanation:

zlopas [31]3 years ago

6 0

Answer:

2000 milliliters, because 1 liter equals 1000 milliliters, so 2 equals 2000! hope this helped!

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10 runners ran fewer than 4 km

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Q28. In a sale, the normal price of a book is reduced by 30%. The sale price of the book is £2.80 Work out the normal price of t

lisov135 [29]

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0.90

Step-by-step explanation:

090. = 0.90

30/2.80

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3 years ago

-30-0.6k <br>what does k equal?

Fed [463]

Answer:

K would equal to:

K= 50

Hope that helps! :)

Step-by-step explanation:

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3 years ago

What would the area of an actual pool be in the scale from the drawing is 3:1000

elena55 [62]

Answer:

If this is the complete question them the answer is 1250 m²

Step-by-step explanation:

the pool in the drawing is 15x7.5 and the scale is 3/1000 so if the size in the drawing is 3 then the actual is 1000.

x=15*1000/3=5000cm which would be 50m

x=7.5*1000/3=2500cm which is 25m

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8 0

3 years ago

The graph of an inverse trigonometric function passes through the point (1, pi/2). Which of the following could be the equation

rodikova [14]

Answer: C) $y=sin^-1 x$

Step-by-step explanation:

Since, the graph of an inverse trigonometric function will pass through the point $(1,\frac{\pi}{2})$ ,

If this point satisfies the function,

For the function $y=cos^{-1} x$

If x = 1

$y=cos^{-1}1=0$

Thus, $(1,\frac{\pi}{2})$ is not satisfying function $y=cos^{-1} x$ ,

⇒ The graph of $y=cos^{-1} x$ is not passing through the point $(1,\frac{\pi}{2})$

For the function $y=cot^{-1}x$

If x = 1

$y=cot^{-1}1=\frac{\pi}{4}$

Thus, $(1,\frac{\pi}{2})$ is not satisfying function $y=cot^{-1}x$ ,

⇒ The graph of $y=cot^{-1}x$ is not passing through the point $(1,\frac{\pi}{2})$

For the function $y=sin^{-1} x$

If x = 1

$y=sin^{-1}1=\frac{\pi}{2}$

Thus, $(1,\frac{\pi}{2})$ is satisfying function $y=sin^{-1} x$ ,

⇒ The graph of $y=sin^{-1} x$ is passing through the point $(1,\frac{\pi}{2})$ .

For the function $y=tan^{-1}x$

If x = 1

$y=tan^{-1}1=\frac{\pi}{4}$

Thus, $(1,\frac{\pi}{2})$ is not satisfying function $y=cos^{-1} x$ ,

⇒ The graph of $y=tan^{-1} x$ is not passing through the point $(1,\frac{\pi}{2})$ .

Hence, Option C is correct.

3 0

3 years ago

Doreen bought 2 liters of lemonade. How many millimeters of lemonade did Doreen buy? ​

Doreen bought 2 liters of lemonade. How many millimeters of lemonade did Doreen buy?