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2 years ago

3

Mathematics

1 answer:

ludmilkaskok [199]2 years ago

3 0

Answer: Yes

Step-by-step explanation:

Each value of y maps onto one value of x.

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Veronika [31]

Answer:

Step-by-step explanation:

5 0

3 years ago

Which of the following systems of linear equations has no solution? x=5,y=3. X=3,y=3. y=3,y=5

Nesterboy [21]

Answer:

X=3,Y=3

Step-by-step explanation:

They have the same location so there wouldn't be any movement so therefore it has no solution.

5 0

4 years ago

Read 2 more answers

I NEED HELP ASAP! In a magic square, the sum of the numbers in each row, column, and diagonal is the same. Write and solve equat

Trava [24]

Answer:

$a=22,\\b=31,\\c=13$

Step-by-step explanation:

When choosing equations to write, make sure you choose a pair that allow you to isolate a variable and solve for it.

Sample solution:

$a+25+28=16+25+34,\\\\a+28=16+34,\\a+28=50,\\a=\boxed{22}$

$16+b+28=16+25+34,\\b+44=75,\\b=\boxed{31}$

$34+c+28=16+25+34,\\c+28=41,\\c=\boxed{13}$

8 0

3 years ago

Jada and Lin are comparing inches and feet. Jada says that the constant of proportionality is 12. Lin says it is 1/2. Do you agr

Pavel [41]

Answer:

i agree with jada

Step-by-step explanation:

i agree with jada because 12 inches are in 1 foot so you need 12 constantly to compare inches and feet

5 0

4 years ago

Recall that m(t) = (1/2)^t/h for radioactive decay, where h is the half-life. Suppose that a 500g sample of phosphorus-32 decays

katrin2010 [14]

The question is incomplete, here is the complete question:

Recall that m(t) = m.(1/2)^t/h for radioactive decay, where h is the half-life. Suppose that a 500 g sample of phosphorus-32 decays to 356 g over 7 days. Calculate the half life of the sample.

<u>Answer:</u> The half life of the sample of phosphorus-32 is $14.28days^{-1}$

<u>Step-by-step explanation:</u>

The equation used to calculate the half life of the sample is given as:

$m(t)=m_o(1/2)^{t/h}$

where,

m(t) = amount of sample after time 't' = 356 g

$m_o$ = initial amount of the sample = 500 g

t = time period = 7 days

h = half life of the sample = ?

Putting values in above equation, we get:

$356=500\times (\frac{1}{2})^{7/h}\\\\h=14.28days^{-1}$

Hence, the half life of the sample of phosphorus-32 is $14.28days^{-1}$

7 0

4 years ago