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PSYCHO15rus [73]
3 years ago
14

Graph the function y=(x-5)^2 identify the vertex,y-intercept,and axis of symmetry

Mathematics
1 answer:
Tasya [4]3 years ago
6 0
Y = (x - 5)²
y = (x - 5)(x - 5)
y = (x² - 5x - 5x +25)
y = x² -10x + 25

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natulia [17]
8/9 x 3/5 = 24/45

24/45 is your answer

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5 0
3 years ago
The first three terms of a sequence are given. Round to the nearest thousandth (if
dalvyx [7]

Answer:

69

Step-by-step explanation:

term = 159 - 3n

4 0
3 years ago
A group of students estimated the length of one minute without reference to a watch or​ clock, and the times​ (seconds) are list
Anit [1.1K]

Answer:

Step-by-step explanation:

Given that a group of students estimated the length of one minute without reference to a watch or​ clock, and the times​ (seconds) are listed below.

Data set is as ollows:

70 79 38 63 44 23 62 61 67 50 61 70 94 87 65

Mean = 62.27Variance =333.35std dev = 18.258std error = 4.714

H0: mu = 60 sec

Ha: mu not equals 60 sec

Mean diff = 2.27

Mean = 62.27Variance =333.35std dev = 18.258std error = 4.714

Test statistic = 2.27/SE =0.4815

p value =0.6376

Since p>0.05, we accept null hypothesis

i.e. there is statistical evidence to say that students are reasonably good at estimating one​ minute

8 0
3 years ago
Simplify (-9)-(9)(-3)-(8)(-7)
Oliga [24]
The answer is 74. The parenthesis is another way of telling you to multiply.
7 0
3 years ago
Read 2 more answers
If the vertex of a parabola is at (2, 3) and the point (0, -1) is also on the parabola, find an equation for the parabola. Write
STALIN [3.7K]

Answer:

y=-1(x-2)^2+3

Step-by-step explanation:

W have been given that the vertex of a parabola is at (2, 3) and the point (0, -1) is also on the parabola. We are asked to find the equation of parabola in the form y=(x-h)^2+k.  

We know that vertex form of parabola in form y=a(x-h)^2+k, where (h,k) in vertex of parabola.  

Upon substituting coordinates of vertex, we will get:

y=a(x-2)^2+3

To find the value of a, we will substitute coordinates of point (0, -1) as:

-1=a(0-2)^2+3

-1=a(4)+3

-1=4a+3

-1-3=4a+3-3

-4=4a

\frac{-4}{4}=\frac{4a}{4}

-1=a

Therefore, our required equation would be y=-1(x-2)^2+3.

3 0
3 years ago
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