100 POINTS HELP ASAP WILL GIVE BRAINLEAST

Mathematics

1 answer:

nika2105 [10]3 years ago

8 0

Answer:

networking is the action or process of interacting with others to exchange information and develop professional or social contacts. A few key strategies to make networking successful are to Build Your Networking Muscle. Practice networking by attending lots of different networking events, Develop Thick Skin. Get comfortable hearing the word “no”, over and over and over again, Be Nice to Everyone You Meet, Be Giving, Grow Your Relationship Database, Communicate, Keep it Simple, and finally Build Report.

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kompoz [17]

To solve this you can multiply the second equation by to get

3x+6y =18

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7y= 14
And get y= 2
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3 years ago

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This is your perfect answer

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3 years ago

The average score on a standardized test is 500 points with a standard deviation of 50 points. What is the probability that a st

Charra [1.4K]

The average score is 500 points and the standard deviation is 50 points.Mean - 2 SD = 500 - 2 * 50 = 500 - 100 = 400It means that more than 400 on the standardized test is more than: Mean - 2 Standard deviations.For the Normal distribution: 100% - 2.5 % = 97.5% = 0.975.Answer: The probability that student scores more than 400 points is 0.975.

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4 years ago

86a^9b^-15/72a^7b^-8

Setler [38]

If I understood this correct
43a^2/36b^7

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3 years ago

Final exam scores are normally distributed with a mean of 74 and a standard deviation of 6. Approximately, what percentage of fi

notka56 [123]

Answer:

81.86%

Step-by-step explanation:

We have been given that final exam scores are normally distributed with a mean of 74 and a standard deviation of 6.

First of all we will find z-score using z-score formula.

$z=\frac{x-\mu}{\sigma}$

$z=\frac{68-74}{6}$

$z=\frac{-6}{6}=-1$

Now let us find z-score for 86.

$z=\frac{86-74}{6}$

$z=\frac{12}{6}=2$

Now we will find P(-1<Z) which is probability that a random score would be greater than 68. We will find P(2>Z) which is probability that a random score would be less than 86.

Using normal distribution table we will get,

$P(-1$