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Vaselesa [24]
3 years ago
13

100 POINTS HELP ASAP WILL GIVE BRAINLEAST

Mathematics
1 answer:
nika2105 [10]3 years ago
8 0

Answer:

networking is the action or process of interacting with others to exchange information and develop professional or social contacts. A few key strategies to make networking successful are to Build Your Networking Muscle. Practice networking by attending lots of different networking events, Develop Thick Skin. Get comfortable hearing the word “no”, over and over and over again, Be Nice to Everyone You Meet, Be Giving, Grow Your Relationship Database, Communicate, Keep it Simple, and finally Build Report.

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M(-3,2) is the midpoint of rs and r has coordinates (6,0). what are the coordinates of s?
nataly862011 [7]
Ley pt S have coordinates (x,y)
we know (x+6)/2=-3
                 x=0
similarly (y+0)/2=2
                y=4
so S=(0,4)
6 0
3 years ago
Factor x2 - 18x + 81. Show your work
tensa zangetsu [6.8K]
To factorise it start with putting the xs in brackets.
(x )(x )
Then you must find 2 numbers which multiply to +81 and sum to -18.
81 is the product of 9×9 or -9×-9.
9+9=+18
-9+-9=-18
So they two numbers must be -9.
So factorised it is (x-9)(x-9) or (x-9)^2
4 0
3 years ago
Read 2 more answers
Which table of ordered pairs represents a proportinal relationship
jeyben [28]

Answer:

where are the tables lol

7 0
3 years ago
Golf in golf , the lowest score wins . One golfer finishes a course at -9 . A second golfer finishes at -12 .
rusak2 [61]

Answer:

The lower score is -12, and he wins buy (12 -9) , or 3 points

3 0
3 years ago
Help with the following problem please
Effectus [21]
Given:
The largest circle has a radius of R=7 units.
Let x be the radius of the large shaded circle.
The small shaded circles have a radius of 1/5 of the large shaded circle.
=> the small shaded circles have a radius of r=x/5

By adding up radii, we have the equation
2(r+x+r)=2(x/5+x+x/5)=2R=2*7=14
Simplify:
7x/5=14/2
x=5
=> r=1

Area of outer circle                  = \pi R^2=\pi7^2=49\pi
Area of large shaded circle      = \pi x^2=\pi5^2=25\pi
Area of 4 small shaded circles = 4\pi r^2=4\pi1^2=4\pi
Total area of shaded circles     =25\pi+4\pi=29\pi

Shaded area as a fraction of that of the outer circle 
=\frac{29\pi}{49\pi}=29/49

3 0
3 years ago
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