Let 2x – y = 3 ——— equation 1
Let x + 5y = 14 ——— equation 2
Making x the subject in eqn 1, = x = y + 3 / 2 ——— eqn 3
• Put eqn 3 in eqn 2
(y + 3 / 2) + 5y = 14
6y = 14 – 3/2
6y = 25/2
y = 25/12
• put y = 25/12 in eqn 3
x = (25/12 + 3/2)
x = 43/12
Answer: Infinite
Step-by-step explanation:
Possible number combinations are 1,1 2,1 3,1 4,1 5,1 6,1 1,2 2,2 3,2 4,2 5,2 6,2 1,3 2,3 3,3 4,3 5,3 6,3 1,4 2,4 3,4 4,4 5,4 6,4 1,5 2,5 3,5 4,5 5,5 6,5 1,6 2,6 3,6 4,6 5,6 and 6,6. of those 36 number combinations the ones that add up to more than 10 include: 4,6 5,5 5,6 6,4 6,5 6,6. thats 6 number combinations. 6/36 of the possible sums of the top faces equal out to 10 or more. 6/36=1/6=0.166666666666666666666666(repeating) and to put that in a percentage, 16.7%
the probability is 16.7%
Hope this helps.
