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3 years ago

What’s the answer to this?

Mathematics

1 answer:

sattari [20]3 years ago

6 0

Answer:

14.42

Step-by-step explanation:

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Jason ha 2,057 stones in his collection.

Rashid [163]

Answer:

2560 stones

Step-by-step explanation:

Jason has 2057 stones

Paul's stones = Jason + 503

= 2057 + 503 = 2560

5 0

3 years ago

What is the length of the hypotenuse, x, if (20,21,x) is a Pythagorean triple?

Sophie [7]

Answer:

Step-by-step explanation:

$(20,21,x) \\Pythagoras -Theorem =\\a^2+b^2 = c^2\\\\20^2 + 21^2 = x^2\\400 + 441 = x^2\\841 = x^2\\Square -root-both-sides\\\sqrt{841} = \sqrt{x^2} \\29 = x\\\\x = 29$

6 0

3 years ago

Read 2 more answers

What is 1546 divided by 12

Flauer [41]

1546/12 = 128.3333333333333333333333333333333333333

8 0

3 years ago

A certain bridge arch is in the shape of half an ellipse 106 feet wide and 33.9 feet high. At what horizontal distance from the

nata0808 [166]

Answer:

The horizontal distance from the center is 49.3883 feet

Step-by-step explanation:

The equation of an ellipse is equal to:

$\frac{x^2}{a^{2} } +\frac{y^2}{b^{2} } =1$

Where a is the half of the wide, b is the high of the ellipse, x is the horizontal distance from the center and y is the height of the ellipse at that distance.

Then, replacing a by 106/2 and b by 33.9, we get:

$\frac{x^2}{53^{2} } +\frac{y^2}{33.9^{2} } =1\\\frac{x^2}{2809} +\frac{y^2}{1149.21} =1$

Therefore, the horizontal distances from the center of the arch where the height is equal to 12.3 feet is calculated replacing y by 12.3 and solving for x as:

$\frac{x^2}{2809} +\frac{y^2}{1149.21} =1\\\frac{x^2}{2809} +\frac{12.3^2}{1149.21} =1\\\\\frac{x^2}{2809}=1-\frac{12.3^2}{1149.21}\\\\x^{2} =2809(0.8684)\\x=\sqrt{2809(0.8684)}\\x=49.3883$

So, the horizontal distance from the center is 49.3883 feet

8 0

3 years ago

Please Help! I don't have much time to finish!

Sav [38]

Answer:

............

Step-by-step explanation:

here........

3 0

2 years ago