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zzz [600]
3 years ago
5

What number has a prime factorization of 2x 5^2

Mathematics
2 answers:
andrew11 [14]3 years ago
8 0
Use math-way it will give u all the answers u need
disa [49]3 years ago
8 0

Answer:

50

Step-by-step explanation:

2x5^2

=2x5x5

=10x5

=50

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What is the rate of change from -1 to 4?
lana66690 [7]

Answer:

5

Step-by-step explanation:

-1+(1)= 0

0+(4)=4

1+4=5

5 0
4 years ago
Michael saw a pair of jeans that he really wants to buy. The price of the jeans is $25.60. He saw that they go on sale for weeke
denis23 [38]

Answer:

$21.76

Step-by-step explanation:

15% of $25.60= $3.84

$25.60-$3.84= $21.76

7 0
4 years ago
Express the integral as a limit of Riemann sums. Do not evaluate the limit. (Use the right endpoints of each subinterval as your
Darina [25.2K]

Answer:

Given definite  integral as a limit of Riemann sums is:

\lim_{n \to \infty} \sum^{n} _{i=1}3[\frac{9}{n^{3}}i^{3}+\frac{36}{n^{2}}i^{2}+\frac{97}{2n}i+22]

Step-by-step explanation:

Given definite integral is:

\int\limits^7_4 {\frac{x}{2}+x^{3}} \, dx \\f(x)=\frac{x}{2}+x^{3}---(1)\\\Delta x=\frac{b-a}{n}\\\\\Delta x=\frac{7-4}{n}=\frac{3}{n}\\\\x_{i}=a+\Delta xi\\a= Lower Limit=4\\\implies x_{i}=4+\frac{3}{n}i---(2)\\\\then\\f(x_{i})=\frac{x_{i}}{2}+x_{i}^{3}

Substituting (2) in above

f(x_{i})=\frac{1}{2}(4+\frac{3}{n}i)+(4+\frac{3}{n}i)^{3}\\\\f(x_{i})=(2+\frac{3}{2n}i)+(64+\frac{27}{n^{3}}i^{3}+3(16)\frac{3}{n}i+3(4)\frac{9}{n^{2}}i^{2})\\\\f(x_{i})=\frac{27}{n^{3}}i^{3}+\frac{108}{n^{2}}i^{2}+\frac{3}{2n}i+\frac{144}{n}i+66\\\\f(x_{i})=\frac{27}{n^{3}}i^{3}+\frac{108}{n^{2}}i^{2}+\frac{291}{2n}i+66\\\\f(x_{i})=3[\frac{9}{n^{3}}i^{3}+\frac{36}{n^{2}}i^{2}+\frac{97}{2n}i+22]

Riemann sum is:

= \lim_{n \to \infty} \sum^{n} _{i=1}3[\frac{9}{n^{3}}i^{3}+\frac{36}{n^{2}}i^{2}+\frac{97}{2n}i+22]

4 0
4 years ago
Which expression uses the greatest common factor and the distributive property to rewrite the sum 42 + 72?
wlad13 [49]

Answer:

The answer is 6(7 + 12) ⇒ 1st answer

Step-by-step explanation:

* Lets explain how to solve the problem

- Factors are the numbers you multiply together to get another number

- Ex: 4 × 5 = 20 ⇒ 4 and 5 are the factors of 20

- Factors of a number n are the numbers that can multiplied together

 to give the number n

- Ex: The factors of 6 are 1 , 2 , 3 , 6 because 1 × 6 = 6 and 2 × 3 = 6

- The distributive property lets you multiply a sum by multiplying each

  term separately and then add the products

- Ex: a(b + c) = ab + ac

* Lets solve the problem

- We want to find the greatest common factor in 42 + 72

∵ 42 = 1 × 42 , 2 × 21 , 3 × 14 , 6 × 7

∴ The factors of 42 are 1 , 2 , 3 , 6 , 7 , 14 , 21 , 42

∵ 71 = 1 × 72 , 2 × 36 , 3 × 24 , 4 × 18 , 6 × 12 , 8 × 9

∴ The factors of 72 are 1 , 2 , 3 , 4 , 6 , 8 , 9 , 12 , 18 , 24 , 36 , 72

- The common factors between 42 and 72 are the bold numbers

∵ The common factors between 42 and 72 are 1 , 2 , 3 , 6

∵ The greatest one of them is 6

∴ The greatest common factor of 42 and 72 is 6

- In the distributive property we have a number multiplying by a sum

 of two numbers

∵ 42 ÷ 6 = 7 and 72 ÷ 6 = 12

- We can write 42 + 72 as 6 × 7 + 6 × 12 and take 6 as a common factor

∵ 42 + 72 = 6 × 7 + 6 × 12

- Take 6 as a common factor

∴ 42 + 72 = 6(7 + 12)

6 0
4 years ago
write the formula of gravitational force between two bodies of mass 'x'and 'y' kept at a distance 'r'​
Rudik [331]

\huge \orange{F =G.\frac{xy}{r^2}}

Step-by-step explanation:

  • Masses of the bodies are x and y

  • Distance at which they are kept is r

  • When two bodies are of masses x and y are placed at a distance r then the gravitational force acting on them is given as:

  • \huge \purple{F =G.\frac{xy}{r^2}}
  • Where G is the gravitational constant.
5 0
2 years ago
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