0,3 is the decimal equivalent of 3/9
5x- 10 = 20
5x -10 +10 = 20 +10
5x = 30
5x/5 =30/5
x = 6
F(x) is continuous for all x.
Pick a point and show that f(x) is either negative or positive. Pick another point and show that f(x) is negative, if positive, or positive, if negative.
At x = 30, f(30) - 1000 = 900 + 10sin(30) - 1000 ≤ 0
Now, show at another point f(x) - 1000 is positive, and hence, there would be root between 30 and such point.
Let's pick 40.
At x = 40, f(40) - 1000 = 1600 + 10sin(40) - 1000 ≥ 0
Since f(x) - 1000 is continuous, there lies a root between 30 and 40, and hence, 30 ≤ c ≤ 40
Answer:
-9x^5(x+3)(x-7)
Step-by-step explanation:
factor out -9x^3 from the expression
