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2 years ago

How long would it take to make 4.5 million dollars with a yearly income of 1000 USD?

Mathematics

1 answer:

Angelina_Jolie [31]2 years ago

6 0

Answer:

4,500 days, years, or months

Your income is $1000, and you are trying to get $4,500,000.

You can do this is by dividing $4,500,000 with $1000.

<u>Division</u>

4500000/1000

Cross out all the numbers of 1000 into 4500000 until you get 1.

Since there are 3 zeros in 1000, you cross 3 out in 4,500,000

So, your answer will be 4,500.

It will take 4,500 days, years, or months (You didn't say the unit)

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Im so confused can someone help me please

hram777 [196]

Answer:

1. false

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Step-by-step explanation:

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5 0

2 years ago

Graph the line with the equation y = -x - 3.

larisa [96]

Answer:

Step-by-step explanation:

$y=-x-3$

This means a graph with a slope of -1, and a y-intercept of -3

8 0

2 years ago

Bob and Maria each purchase steak from the butcher. Maria selects a cut that costs $19.98 per pound. Bob’s selection costs $13.9

Sidana [21]

Answer:

Bob is paying more for the actual steak

Step-by-step explanation:

we know that

Maria selects a cut that costs $19.98 per pound (Maria's steak is all meat)

Bob’s selection costs $13.98 per pound (Bob’s cut of beef is 1⁄3 bone and fat)

Bob's cut is 2/3 all meat

Find the unit rate of Bob's cut for all meat

$\frac{13.98}{(2/3)} \frac{\$}{pounds} =20.97\frac{\$}{pounds}$

therefore

$\$20.97> \$19.98$

Bob is paying more for the actual steak

8 0

2 years ago

Sophie earns 6% interest from her bank. If she has $456 in the bank, how much interest will she earn?

Tresset [83]

Sophie would earn $27.36 from interest because 456 divided by 0.06 equals 27.36

3 0

2 years ago

Evaluate each limit. Give exact answers.

tamaranim1 [39]

Answer:

Given that 1 and 4 are vertical asymtotes we have;

(a) -∞

(b) +∞

(d) -∞

Step-by-step explanation:

(a) For the function;

$\lim_{x\rightarrow 4^{-}}\left (\dfrac{2\cdot x^{2}+13\cdot x+20}{x^{2}-5\cdot x+4} \right )$

We have the denominator given by the expression, x² - 5·x + 4 which can be factorized as (x - 4)(x - 1)

Therefore, as the function approaches 4 from the left [lim (x → 4⁻)] gives;

$\lim_{x\rightarrow 4^{-}}\left (\dfrac{2\cdot x^{2}+13\cdot x+20}{(x - 1)\cdot (x - 4)} \right )$ $\lim_{x\rightarrow 4^{-}}\left (\dfrac{2\cdot x^{2}+13\cdot x+20}{(3.999 - 1)\cdot (3.999 - 4)} \right )$ $\lim_{x\rightarrow 4^{-}}\left (\dfrac{2\cdot x^{2}+13\cdot x+20}{(2.999)\cdot (-0.001)} \right )$ $=- \infty$

(b) Similarly, we have;

$\lim_{x\rightarrow 4^{+}}\left (\dfrac{2\cdot x^{2}+13\cdot x+20}{x^{2}-5\cdot x+4} \right )$

We have the denominator given by the expression, x² - 5·x + 4 which can be factorized as (x - 4)(x - 1)

Therefore, as the function approaches 4 from the right [lim (x → 4⁺)] gives;

$\lim_{x\rightarrow 4^{+}}\left (\dfrac{2\cdot x^{2}+13\cdot x+20}{(x - 1)\cdot (x - 4)} \right )$ $\lim_{x\rightarrow 4^{+}}\left (\dfrac{2\cdot x^{2}+13\cdot x+20}{(4.0001 - 1)\cdot (4.0001 - 4)} \right )$ $\lim_{x\rightarrow 4^{+}}\left (\dfrac{2\cdot x^{2}+13\cdot x+20}{(3.0001)\cdot (0.0001)} \right )$ $= +\infty$

(c)

$\lim_{x\rightarrow 1^{-}}\left (\dfrac{2\cdot x^{2}+13\cdot x+20}{x^{2}-5\cdot x+4} \right )$

We have the denominator given by the expression, x² - 5·x + 4 which can be factorized as (x - 4)(x - 1)

Therefore, as the function approaches 1 from the left [lim (x → 1⁻)] gives;

$\lim_{x\rightarrow 1 ^{-}}\left (\dfrac{2\cdot x^{2}+13\cdot x+20}{(x - 1)\cdot (x - 4)} \right )$ $\lim_{x\rightarrow 1^{-}}\left (\dfrac{2\cdot x^{2}+13\cdot x+20}{(0.999 - 1)\cdot (0.999 - 4)} \right )$ $\lim_{x\rightarrow 4^{+}}\left (\dfrac{2\cdot x^{2}+13\cdot x+20}{(-0.001)\cdot (-3.001)} \right )$ $=+ \infty$

(d) As the function approaches 1 from the right [lim (x → 1⁺)]

We have;

$\lim_{x\rightarrow 1^{+}}\left (\dfrac{2\cdot x^{2}+13\cdot x+20}{(1.0001 - 1)\cdot (1.0001 - 4)} \right )$ = $\lim_{x\rightarrow 1^{+}}\left (\dfrac{2\cdot x^{2}+13\cdot x+20}{(0.0001)\cdot (-2.999)} \right ) =- \infty$

7 0

3 years ago