So the right answer is 9g^20p^16
look at the attached picture
Hope it will help you
Good luck on your assignment
complette the square to get vertex form or y=a(x-h)^2+k
(h,k) is vertex
1. group x terms, so for y=ax^2+bx+c, do y=(ax^2+bx)+c
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2, factor out the leading coefinet (constant in front of the x^2 term), basicallly factor out a
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3. take 1/2 of the linear coefient (number in
front of the x), and square it ,then add negative and positive of it
inside parnthases
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4. complete the squre and expand
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so
y=-1/4x^2+4x-19
group
y=(-1/4x^2+4x)-19
undistribute -1/4
y=-1/4(x^2-16x)-19
take 1/2 of -16 and squer it to get 64 then add neg and pos inside
y=-1/4(x^2-16x+64-64)-19
factorperfect square
y=-1/4((x-8)^2-64)-19
expand
y=-1/4(x-8)^2+16-19
y=-1/4(x-8)^2-3
vertex is (8,-3)
Answer:
(d) Yes. (3x + 3) - (2x + 2y + 4)
Step-by-step explanation:
The first answer choice results in a monomial, -2y
The second answer choice results in a binomial, x -y
The third answer choice is proved wrong by the fourth answer choice.
The fourth answer choice results in x -2y -1, a trinomial.
Answer:
True
Step-by-step explanation:
Even though we cannot see the parallelogram, we can assume the dimensions of the original parallelogram is height= 3 and base= 6.
If we double the dimensions, we get:
height=6 band base=12.
The area of the original parallelogram is 18 square units.
The area of the enlarged parallelogram is 6×12= 72 square units.
Now,
Hence, the area of the larger parallelogram is 4 times more than the original.
