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4 years ago

What is ......(23×10)+(23×7)=

Mathematics

1 answer:

babunello [35]4 years ago

5 0

Answer:

391

Step-by-step explanation:

(23 x 10) + (23 x 7) =

230 + 161 =

391

Hope this helps! Please mark as brainliest.

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Write the equation of a line:

yawa3891 [41]

a) Line parallel to the line 3x+5y=-10 is -6x-10y=9

b) Line parallel to the line 2y-4x=5 and which goes through the point

(3,7) is y= 2x-1.

c) Line perpendicular to the line 8x+6y=-1 and which goes through the

point (-2,1) is 4y= 3x+ 10

<h3>What is equation of line?</h3>

The standard form of equation of a line is ax + by + c = 0. Here a, b, are the coefficients, x, y are the variables, and c is the constant term. It is an equation of degree one, with variables x and y.

a) Equation parallel to 3x+5y=-10 is

-6x-10y=9

So, it satisfies: $\frac{a_1}{a_2} = \frac{b_1}{b_2} \neq \frac{c_1}{c_2}$

b)given equation into the form of y=mx+c,

2y-4x=5

we can find the gradient of the line.

2y= 5+4x

y= $\frac{5}{2}$ + 2x

Hence, the gradient is 2.

As, Parallel lines have the same gradient

Thus the line would also have a gradient of 2.

Substitute m=2 into the equation:

y= 2x +c

To find the value of c, substitute a pair of coordinates.

When x=3, y=7,

7= 2(3) +c

7= 6 +c

c=6-7

c= -1

So, equation of line be: y= 2x-1.

c) Given: 8x+6y=-1

6y= -1-8x

y= $\frac{-1}{6} -\frac{4}{3}x$

Hence, m= $-\frac{4}{3}$

We know, if two lines are perpendicular have m and m' as slope then,

m*m'=-1

$\frac{-4}{3} *m'=-1$

m'= $\frac{3}{4}$

Now, y= $\frac{3}{4}$ x +c

Put x= -1 and y=1

then, 1= $\frac{3}{4}$ (-2) + c

c= $\frac{5}{3}$

So, y= $\frac{3}{4}$ x + $\frac{5}{2}$

4y= 3x+ 10

Learn more about equation of line here:

brainly.com/question/14577230

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5 0

3 years ago

Find the coordinates of the midpoint M of ST.Then find the distance between points S and T.Round the distance to the nearest ten

Norma-Jean [14]

Answer:

Shjsdududufuududidididiiddud

Step-by-step explanation:

Dhhdrhrhrhrhrhrhrjjr

6 0

4 years ago

2% of the population suffers from the terrible disease conditionitis. The test for conditionitis comes back positive 98% of the

vlabodo [156]

Answer:

8% probability that he or she actually has the disease

Step-by-step explanation:

We use the Bayes Theorem to solve this question.

Bayes Theorem:

Two events, A and B.

$P(B|A) = \frac{P(B)*P(A|B)}{P(A)}$

In which P(B|A) is the probability of B happening when A has happened and P(A|B) is the probability of A happening when B has happened.

If a randomly chosen person is given the test and the test comes back positive for conditionitis, what is the probability that he or she actually has the disease?

This means that:

Event A: Test comes back positive.

Event B: Having the disease.

Test coming back positive:

2% have the disease(meaning that P(B) = 0.02), and for those, the test comes positive 98% of the time. This means that $P(A|B) = 0.98$