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VMariaS [17]
3 years ago
7

Andrea was asked to find the value of –32 × 9 × 5/4 . How can Andrea make this problem easier to compute?

Mathematics
1 answer:
Volgvan3 years ago
8 0

Answer:

divide the 32 by 4:

then the equation becomes:

8 x 9 x 5 = 360

this is the same as 32 x 9 x 5/4 = 360

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50 + 50 = 100 right <br> sure
Lerok [7]

Answer:

yes  

Step-by-step explanation:

good job

7 0
3 years ago
Read 2 more answers
Please divide 4⁄6 ÷ 2⁄6
dolphi86 [110]

4/6 divided by 2/6 is 2.

you multiply the 4/6 by 6/2 to get 24/12. You then simplify it and get 2 as your answer.

6 0
4 years ago
(no links) PLS HELP AGAIN I LOVE U
Minchanka [31]

y = 3(x + 4)^2 + 31

Step-by-step explanation:

We can convert the given quadratic equation into its vertex form by completing the square:

y = 3x^2 + 24x + 43

= 3(x^2 + 8x) + 43

= 3(x^2 + 8x + 4) + 31

= 3(x + 4)^2 + 31

This is the vertex form of the given quadratic equation with (-4, 31) as its vertex

4 0
3 years ago
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Fofino [41]

Answer:

it decended 239 feet per minute

Step-by-step explanation:

4 0
2 years ago
The heights of baby giraffe are normally distributed with a mean of 63.6 inches and a standard deviation of 2.5 inches. If 100 b
ANEK [815]

Answer:

P(\bar X

And we can solve this using the following z score formula:

z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And if we use this formula we got:

z = \frac{63-63.6}{\frac{2.5}{\sqrt{100}}}= -2.4

So we can find this probability equivalently like this:

P( Z

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the heights of a population, and for this case we know the distribution for X is given by:

X \sim N(63.6,2.5)  

Where \mu=63.6 and \sigma=2.5

We select n =100. Since the distribution for X is normal then we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

We want this probability:

P(\bar X

And we can solve this using the following z score formula:

z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And if we use this formula we got:

z = \frac{63-63.6}{\frac{2.5}{\sqrt{100}}}= -2.4

So we can find this probability equivalently like this:

P( Z

4 0
4 years ago
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