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VMariaS [17]
2 years ago
7

Andrea was asked to find the value of –32 × 9 × 5/4 . How can Andrea make this problem easier to compute?

Mathematics
1 answer:
Volgvan2 years ago
8 0

Answer:

divide the 32 by 4:

then the equation becomes:

8 x 9 x 5 = 360

this is the same as 32 x 9 x 5/4 = 360

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A volume of a cylinder is given by the expression 6n2 – 13n – 28. The area of the base is 3n + 4.
olga nikolaevna [1]
Volume of cylinder = Base Area x Height

Height = Volume/Base

Height = (6n² -13n -28)/(3n+4)
Perform this division and you will get Height = 2n-7


9 0
3 years ago
Read 2 more answers
A. Two orders for birthday parties come in and you are responsible for getting the order ready. Both orders ask for 192 ounces o
Colt1911 [192]

Answer:

64

Step-by-step explanation:

this should be easy cause the 64 is bigger, so the parts are smaller. 192 divided by 64 is 3. 192 divided by 12 is 16. multiply, Yada yada… you get 64 is better!

7 0
2 years ago
Factors and common factors of 24,64,88
babunello [35]
24- 1,2,3,4,6,8,12,24
64-1,2,4,8,16,32,64
88-1,2,4,8,11,22,44,88

Here are all the factors.^^
The common factors are 1,2,3,4,6
Hope this helps!
8 0
3 years ago
!!PLEASE HELP!! CAN GIVE BRAINLIEST!!
lara31 [8.8K]

Answer:

'The closest distance between Earth and Jupiter is greater than the closest distance between Earth and Mercury by approximately 7.66 times'.

Step-by-step explanation:

We are given that,

Distance between Earth and Jupiter = 5.9 × 10⁸ kilometers

Distance between Earth and Mercury = 7.7 × 10⁷ = 0.77 × 10⁸ kilometers

So, we see that,

5.9 × 10⁸ > 0.77 × 10⁸

Also, Ratio = \frac{5.9\times 10^8}{0.77\times 10^8} =7.66

That is,

'The closest distance between Earth and Jupiter is greater than the closest distance between Earth and Mercury by approximately 7.66 times'.

4 0
3 years ago
A panda and a giraffe start moving towards each other when they are 300 feet apart. The panda is running at a speed of P feet pe
liq [111]

Answer:

(2P + G) feet/min

Step-by-step explanation:

Speed of the panda = P

Speed of the giraffe = P + G

Thus,

Speed of Panda + Speed of Giraffe = approaching time

= P + P + G

= <u>2P + G</u>

Thus, The panda and the giraffe are approaching each other at a rate

of <u>(2P + G) ft/min</u>

<u></u>

<em>Hope it helps :)</em>

6 0
3 years ago
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