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Free_Kalibri [48]
2 years ago
7

Help please ..............​

Mathematics
1 answer:
vlada-n [284]2 years ago
5 0

Answer:

6x is indeed the Greatest Common Factor.

Step-by-step explanation:

6x[3 - y² + 2y⁶]

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Describe julius caesar as a child
lianna [129]

Answer:

You dare challenge me...

Step-by-step explanation:

Gaius Julius Caesar was a Roman general and statesman who played a critical role in the events that led to the demise of the Roman Republic and the rise of the Roman Empire. In 60 BC, Caesar, Crassus and Pompey formed the First Triumvirate, a political alliance that dominated Roman politics for several years.

8 0
3 years ago
Write a ratio this is equivalent to 9/27
tresset_1 [31]
9/27

there are infinite ratios equal to 9/27


one if the ratio is 1/3
8 0
3 years ago
Kerry has a new phone plan. It works by charging $20 per month and then $0.10 for each minute over 200 minutes.
REY [17]

Answer:

(40-20)/.10

Step-by-step explanation:

40-20 is 20, 20 divided by .10 is 200, she used 200 extra minutes.

3 0
2 years ago
Write a polynomial function of least degree with the given zero. -1+ √ 2, √ 3
kirill115 [55]

Answer:

f(x) = x^{4} + 2x³ - 4x² - 6x + 3

Step-by-step explanation:

Note that radical zeros occur in conjugate pairs, thus

- 1 + \sqrt{2} is a zero then - 1 - \sqrt{2} is also a zero

\sqrt{3} is a zero then - \sqrt{3} is also a zero

Thus the corresponding factors are

(x - (- 1 + \sqrt{2}) ), (x - (- 1 - \sqrt{2}) ), (x - \sqrt{3}), (x - (- \sqrt{3})), that is

(x + 1 - \sqrt{2}), (x + 1 + \sqrt{2}), (x - \sqrt{3}), (x + \sqrt{3})

The polynomial is then the product of the roots

f(x) = (x + 1 - \sqrt{2})(x + 1 + \sqrt{2})(x - \sqrt{3})(x + \sqrt{3})

     = ((x + 1)² - (\sqrt{2})²)((x² - (\sqrt{3})²)

     = (x² + 2x + 1 - 2)(x² - 3)

     = (x² + 2x - 1)(x² - 3) ← distribute

     = x^{4} - 3x² + 2x³ - 6x - x² + 3

     = x^{4} + 2x³ - 4x² - 6x + 3

6 0
3 years ago
Need help please, does any one know how to do this​
ziro4ka [17]

Answer:

  • (6-u)/(2+u)
  • 8/(u+2) -1
  • -u/(u+2) +6/(u+2)

Step-by-step explanation:

There are a few ways you can write the equivalent of this.

1) Distribute the minus sign. The starting numerator is -(u-6). After you distribute the minus sign, you get -u+6. You can leave it like that, so that your equivalent form is ...

  (-u+6)/(u+2)

Or, you can rearrange the terms so the leading coefficient is positive:

  (6 -u)/(u +2)

__

2) You can perform the division and express the result as a quotient and a remainder. Once again, you can choose to make the leading coefficient positive or not.

  -(u -6)/(u +2) = (-(u +2)-8)/(u +2) = -(u+2)/(u+2) +8/(u+2) = -1 + 8/(u+2)

or

  8/(u+2) -1

Of course, anywhere along the chain of equal signs the expressions are equivalent.

__

3) You can separate the numerator terms, expressing each over the denominator:

(-u +6)/(u+2) = -u/(u+2) +6/(u+2)

__

4) You can also multiply numerator and denominator by some constant, say 3:

  -(3u -18)/(3u +6)

You could do the same thing with a variable, as long as you restrict the variable to be non-zero. Or, you could use a non-zero expression, such as 1+x^2:

  (1+x^2)(6 -u)/((1+x^2)(u+2))

7 0
3 years ago
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