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guajiro [1.7K]
3 years ago
5

Toby has already spent 22 minutes on the phone, and he expects to spend 2 more minutes with every phone call he routes. In all,

how many phone calls does Toby have to route to spend a total of 42 minutes on the phone?
_____ phone calls
Mathematics
1 answer:
Scilla [17]3 years ago
4 0
10.
42-22 is 20
20 minutes divided by 2 minutes is 10
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Given that f (x) = x^2 - 5x and g (x) x + 4
velikii [3]
1) (x-2)^2
2)-4x(x+5)

pls mark as brainliest:))
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3 years ago
A dress needs 3 1/4 yards of fabric to make. If the matching jacket requires 5/6 less yards of fabric. How much fabric is needed
oksian1 [2.3K]
Fabric needs to make a dress = 3 1/4
fabric needs to make jacket= 3 1/4 - 5/6
= 29/12 or 2 5/12
Hence total fabric needed for both pieces is
= 3 1/4 + 2 5/12
= 68/12 or 5 8/12 or 5 2/3 yards
3 0
3 years ago
Find a irrational number between 7.7 and 7.9 explain why it’s irrational
Alexeev081 [22]
7.77777777 repeating

Irrational numbers are:

Numbers that repeat 
7.7777777 repeats the number 7 after the decimal

Numbers that CANNOT be written as a simple fraction.
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~Aamira~

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8 0
3 years ago
Read 2 more answers
Find lcm and hcf of 168 and 126​
Nuetrik [128]

Answer:

LCM is 504. GCF is 42

Step-by-step explanation:

6 0
3 years ago
A test is used to assess readiness for college. In a recent​ year, the mean test score was 20.3 and the standard deviation was 4
Vlada [557]

Answer:

\mu = 20.3

\sigma = 4.9

And we can find the limits in order to consider values as significantly low and high like this:

Low\leq \mu -2 \sigma= 20.3- 2*4.9 = 10.5

High\geq \mu +2 \sigma= 20.3+ 2*4.9 = 30.1

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Solution to the problem

For this case we can consider a value to be significantly low if we have that the z  score is lower or equal to - 2 and we can consider a value to be significantly high if its z score is  higher tor equal to 2.

For this case we have the mean and the deviation given:

\mu = 20.3

\sigma = 4.9

And we can find the limits in order to consider values as significantly low and high like this:

Low \leq \mu -2 \sigma= 20.3- 2*4.9 = 10.5

High\geq \mu +2 \sigma= 20.3+ 2*4.9 = 30.1

6 0
3 years ago
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