<h3>
Answer: <u>
11</u>
units to the <u>
right</u>
and <u>
3</u>
units <u>
down</u></h3>
====================================================
Explanation:
Plot the two points on the same xy grid (refer to the diagram below). Once this is done, the answer probably will become apparent. We should move point B 11 units to the right so that we move directly over top point B'. Count out the spaces to see why this is the case, or you can subtract the x coordinates and apply absolute value
|x1-x2| = |-5 - 6| = 11
Then we need to move 3 units down to finally arrive at point B'
---------------------------
A non-visual or non-graph approach could look like this:
B is at (-5,-2) while B' is at (6,-5)
Focus on the x coordinates for now. Like before, we subtract the x coordinates and apply absolute value to get |x1-x2| = |-5 - 6| = 11. This is the "11 units to the right" motion.
Do the same for the y coordinates to get |y1-y2| = |-2-(-5)| = 3. We move down because the y coordinate of B' is further away from 0 compared to the y coordinate of B.
In short, we apply the translation rule
to describe the motion of right 11, down 3.
Answer:
<em>0.5seconds later</em>
Step-by-step explanation:
Given the height modeled by the equation:
s(t) = -16t^2 + 16t + 1152
The velocity of the object at the moon surface is zero
ds(t)/dt = 0
ds(t)/dt = -32t + 16
0 = -32t + 16
32 t = 16
t = 16/32
t = 1/2
t = 0.5seconds
<em>Hence the object strikes the moon surface 0.5seconds later</em>
Answer:
x = (W - y)/3
Step-by-step explanation:
3x+y=W
3x = W - y
x = (W - y)/3
Answer:

Step-by-step explanation:
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