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ivann1987 [24]
3 years ago
10

Consider the algorithm for determining whether a sequence of parentheses is balanced (has correct nesting). The pseudo code for

this algorithm appears below.
Initialize a boolean variable validExpression to true.
while (there are more symbols in the expression){

look at the next symbol
if symbol is a {, [, or (
push it on the stack
if it is a }, ], or ){ if the stack is empty then return false
else pop the stack
}

if the element popped is not the match for symbol then return false
}
if the stack is not empty then return false, else return true.

Required:
What is the maximum number of symbols that will appear on the stack at any time for the sequence { [ ( ) ] [ ( ) ] [ ( ) ] }? why?
Computers and Technology
1 answer:
Katarina [22]3 years ago
6 0

Answer:

3

Explanation:

The maximum number of symbols that will be on the stack would be 3. This is because according to the pseudocode every time that a left-facing symbol ( }, ], or ) ) it automatically ends the function or pops the last element in the stack. Therefore, the longest sequence of right-facing symbols would also equal the maximum number of symbols in the stack. In the sequence passed in the question, this would mean that the longest stack would be 3 and include the following sequence {[(

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Assume the availability of a function named oneMore. This function receives an integer and returns one more than its parameter.
jek_recluse [69]

Answer:

oneMore(oneMore(oneMore(oneMore(oneMore(0)))))

Explanation:

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  • So doing step-by-step:

             (oneMore(0))=1

             (oneMore(oneMore(0)))=2

             (oneMore(oneMore(oneMore(0))))=3

             (oneMore(oneMore(oneMore(oneMore(0)))))=4

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