The formula is
A=p (1+r/k)^kt
A future value 3000
P present value 150
R interest rate 0.025
T time?
3000=150 (1+0.025/12)^12t
Solve for t
3000/150=(1+0.025/12)^12t
Take the log
Log (3000/150)=log (1+0.025/12)×12t
12t=Log (3000/150)÷log (1+0.025/12)
T=(log(3,000÷150)÷log(1+0.025÷12))÷12
T=119.95 years
Honestly I don’t remember how to do this but u can try .083 but don’t count on it
The distance is approximately 703 kilometers.
To travel that in 12 hours, a car has to go at 703/12=58.583 km/h
The linear equation/slope intercept form is y=mx+b
M is the slope and b is the y-intercept.
So the equation would be: y=2x+4
Answer:
14
Explanation:
Parenthesis, Exponents, Multiply, Divide, Add, Subtract
27 ÷ 9 = 3
3 · 2 = 6
8 + 6 = 14
