Question

Consider the 6 x 9 inch rectangular cake that is 2 inches deep. If you cover the cake with frosting excluding the bottom, what is the surface area that will be covered with frosting?

Answer 1

Total area of the ends: 2(2")(6") = 24 in^2

Total area of the sides: 2(2")(9") = 36 in^2

Are of the bottom : 1(6")(9") = 54 in^2

Total surface area to be covered = (24+36+54) in^2

Answer 2

Answer:  $114\ inches^2$

Step-by-step explanation:

Given: The dimensions of the base of  rectangular cake is $6\times9$ inch.

The length of the rectangular cake = 9 inches

The width of the rectangular cake = 6 inches

The height of the rectangular cake = 2 inches

The surface area of rectangular cake if excluding the bottom will be given by :-

$\text{Surface Area}=2h(l+w)+lw\\\\\Rightarrow\ \text{Surface Area}=2(2)(9+6)+(9\times6)\\\\\Rightarrow\ \text{Surface Area}=4(15)+54\\\\\Rightarrow\ \text{Surface Area}=60+54\\\\\Rightarrow\ \text{Surface Area}=114\ inches^2$