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Cerrena [4.2K]
3 years ago
7

Which of the following is NOT a monomial? a. x-4 b. 22xy c. 3 d. -11x

Mathematics
1 answer:
qwelly [4]3 years ago
7 0
Answer is (a)
its a binomial
not a monomial
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Does 30, 40, 45 make a right triangle?
mr Goodwill [35]

Answer:

no these degrees do not make a right triangle

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2 years ago
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Yvonne had a rope that measured 2/5 long. She
yawa3891 [41]

Answer:

Number of smaller ropes she can make from the larger rope = 2/3

Step-by-step explanation:

Total length of rope = 2/5 ft

Length of smaller rope = 3/5 ft

How many smaller ropes can she make from the larger rope?

Number of smaller ropes she can make from the larger rope = Total length of rope / Length of smaller rope

= 2/5 ÷ 3/5

= 2/5 × 5/3

= (2*5)/(5*3)

= 10/15

= 2/3

Number of smaller ropes she can make from the larger rope = 2/3

7 0
3 years ago
Find the equation of the line using y=mx+b form thank you :)
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The answer to the question

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3 years ago
Find the area under the standard normal probability distribution between the following pairs of​ z-scores. a. z=0 and z=3.00 e.
prohojiy [21]

Answer:

a. P(0 < z < 3.00) =  0.4987

b. P(0 < z < 1.00) =  0.3414

c. P(0 < z < 2.00) = 0.4773

d. P(0 < z < 0.79) = 0.2852

e. P(-3.00 < z < 0) = 0.4987

f. P(-1.00 < z < 0) = 0.3414

g. P(-1.58 < z < 0) = 0.4429

h. P(-0.79 < z < 0) = 0.2852

Step-by-step explanation:

Find the area under the standard normal probability distribution between the following pairs of​ z-scores.

a. z=0 and z=3.00

From the standard normal distribution tables,

P(Z< 0) = 0.5  and P (Z< 3.00) = 0.9987

Thus;

P(0 < z < 3.00) = 0.9987 - 0.5

P(0 < z < 3.00) =  0.4987

b. b. z=0 and z=1.00

From the standard normal distribution tables,

P(Z< 0) = 0.5  and P (Z< 1.00) = 0.8414

Thus;

P(0 < z < 1.00) = 0.8414 - 0.5

P(0 < z < 1.00) =  0.3414

c. z=0 and z=2.00

From the standard normal distribution tables,

P(Z< 0) = 0.5  and P (Z< 2.00) = 0.9773

Thus;

P(0 < z < 2.00) = 0.9773 - 0.5

P(0 < z < 2.00) = 0.4773

d.  z=0 and z=0.79

From the standard normal distribution tables,

P(Z< 0) = 0.5  and P (Z< 0.79) = 0.7852

Thus;

P(0 < z < 0.79) = 0.7852- 0.5

P(0 < z < 0.79) = 0.2852

e. z=−3.00 and z=0

From the standard normal distribution tables,

P(Z< -3.00) = 0.0014  and P(Z< 0) = 0.5

Thus;

P(-3.00 < z < 0 ) = 0.5 - 0.0013

P(-3.00 < z < 0) = 0.4987

f. z=−1.00 and z=0

From the standard normal distribution tables,

P(Z< -1.00) = 0.1587  and P(Z< 0) = 0.5

Thus;

P(-1.00 < z < 0 ) = 0.5 -  0.1586

P(-1.00 < z < 0) = 0.3414

g. z=−1.58 and z=0

From the standard normal distribution tables,

P(Z< -1.58) = 0.0571  and P(Z< 0) = 0.5

Thus;

P(-1.58 < z < 0 ) = 0.5 -  0.0571

P(-1.58 < z < 0) = 0.4429

h. z=−0.79 and z=0

From the standard normal distribution tables,

P(Z< -0.79) = 0.2148  and P(Z< 0) = 0.5

Thus;

P(-0.79 < z < 0 ) = 0.5 -  0.2148

P(-0.79 < z < 0) = 0.2852

8 0
3 years ago
What is the length of the missing leg?
sp2606 [1]

Answer:

a=12

Step-by-step explanation:

Pythagorean Theorem: a^{2}+b^{2}=c^{2}

In this case, a = 9, b = a, and c = 15.

9^{2}+a^{2}=15^{2}

81+a^{2}=225

The, we subtract 81 from both sides getting:

a^{2}=144,

Then, a=12

6 0
2 years ago
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