All categories

3 years ago

5 x 8 + 6 / 6 - 12 x 2

Mathematics

1 answer:

Whitepunk [10]3 years ago

4 0

Yes, you did it right. That is the correct answer! Nice job!

You might be interested in

The population of mosquitoes in a certain area increases at a rate proportional to the current population, and in the absence of

Alexandra [31]

Answer:

Population of mosquitoes in the area at any time t is:

$P(t) =504,943.26 -104,943.26e^{0.693t}$

Step-by-step explanation:

assume population at any time t = P(t)

population increases at a rate proportional to the current population:

⇒dP/dt ∝ P

$\implies \frac{dP}{dt} =kP$ ----(1)

where k is constant rate at which population is doubled

solving (1)

$ln|P(t)|=kt +C\\P(t)= e^{kt+C}\\P(t)=Ce^{kt}$

$t=0\\P(0) = P_{o}\\\implies C= P_{o}\\P(t) =P_{o}e^{kt}\\$ ---- (2)

initial population = 400,000

population is doubled every week

⇒P(1)=2P(0)

Using (2)

$P_{o}e^{k(1)} = 2P_{o} e^{k(0)}\\$

$e^{k} =2\\k=ln|2|\\$

In presence of predators amount is decreased by 50,000 per day

Then amount decreased per week = 350,000

In this case (1) becomes

$\frac{dP}{dt}=kP-350,000\\\frac{dP}{dt} - kP=-350,000\\$ ---(3)

solving (3) by calculating integrating factor

$I.F=e^{\int-k dt}$

Multiplying I.F with all terms of (3)

$e^{-kt}\frac{dP}{dt} - ke^{-kt}P =-350,000 e^{-kt}\\\frac{d}{dt}(e^{-kt}P) = -350,000 e^{-kt}$

Integrating w.r.to t

$e^{-kt}P(t)= \frac{350,000e^{-kt}}{k} +C$

$P(t) =\frac{350,000}{k} +Ce^{kt}\\$

$k=ln|2| =0.693$

$P(t) =504,943.26 + Ce^{0.693t}\\$

at t=0

$P(0) =504,943.26 + Ce^{0.693(0)}$

$400,000 =504,943.26 + C$

$C = -104,943.26$

So, population of mosquitoes in the area at any time t is

$P(t) =504,943.26 -104,943.26e^{0.693t}$

6 0

3 years ago

Theresa finds a shirt on sale at the store. The regular price of the shirt is $32.00. But there is a 20% off sale today. Theresa

telo118 [61]

Answer:

Step-by-step explanation:

Given tgat:

Regular price = $32

Discount = 20%

Sale tax = 8.1%

8 0

3 years ago

What is the difference in price per kg between chicken sold at $23.24/kg and turkey sold at $5.17/250 g?

Fed [463]

There are 1000 grams in 1 KILOgram.

therefore in 23.24/kg can be just written using grams as 23.24/1000, since 1kg = 1000 g.

so the price of the chicken per gram is then 23.24/1000 or $0.02324 per gram, roughly 2 and 1/3 pennies per gram.

and the turkey is 5.17/250 in grams already, that gives us $0.02068 per gram, which is roughly 2 pennies.

well, their price difference is 0.02324 - 0.02068, which is 0.00256 per gram unit.

since we know there are 1000 grams in 1 Kg, how much is that for 1000 grams or a Kg? 0.00256 * 1000 or $2.56.

8 0

3 years ago

4.2.9<br> For f(x)=2*, find f (7/2) <br> How do you solve this

postnew [5]

Step-by-step explanation:

f(x)=2*,

it will mean, f(7/2)=2

f= 4/7

7 0

3 years ago

URGENT. Geometric Probability.

hichkok12 [17]