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pashok25 [27]
2 years ago
14

5 x 8 + 6 / 6 - 12 x 2

Mathematics
1 answer:
Whitepunk [10]2 years ago
4 0

Yes, you did it right. That is the correct answer! Nice job!

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The difference of a number and 6 is less than 1. <br> Must be a inequality
pentagon [3]

Answer:

x-6 <1

Step-by-step explanation:

6 0
3 years ago
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Help !! Please I can’t find the answer
SVETLANKA909090 [29]

Answer:

\large\boxed{r^2=(x+5)^2+(y-4)^2}

Step-by-step explanation:

The equation of a circle:

(x-h)^2+(y-k)^2=r^2

<em>(h, k)</em><em> - center</em>

<em>r</em><em> - radius</em>

<em />

We have diameter endpoints.

Half the length of the diameter is the length of the radius.

The center of the diameter is the center of the circle.

The formula of a distance between two points:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Substitute the coordinates of the given points (-8, 2) and (-2, 6):

d=\sqrt{(6-2)^2+(-2-(-8))^2}=\sqrt{4^2+6^2}=\sqrt{16+36}=\sqrt{52}

The radius:

r=\dfrac{d}{2}\to r=\dfrac{\sqrt{52}}{2}

The formula of a midpoint:

\left(\dfrac{x_1+x_2}{2},\ \dfrac{y_1+y_2}{2}\right)

Substitute:

x=\dfrac{-8+(-2)}{2}=\dfrac{-10}{2}=-5\\\\y=\dfrac{2+6}{2}=\dfrac{8}{2}=4

(-5,\ 4)\to h=-5,\ k=4

Finally:

(x-(-5))^2+(y-4)^2=\left(\dfrac{\sqrt{52}}{2}\right)^2\\\\(x+5)^2+(y-4)^2=\dfrac{52}{4}\\\\(x+5)^2+(y-4)^2=13

5 0
3 years ago
What is a factor greater than one?
topjm [15]
2 is greater than one and 3 and 4 and 5
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3 years ago
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IMMEDIATE HELP PLS THANKS &lt;33
Ksenya-84 [330]
Reflect across the y axis and moved through the translation x = 2
3 0
3 years ago
30 + q = 43 show work PLEASEE HELP
Ira Lisetskai [31]

Answer:

13

Step-by-step explanation:

43 - 30 = 13

q = 13

3 0
3 years ago
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