Ask question

Ask question

All categories

3 years ago

9

find the total volume of a prism formed by joining end to end of two cubes each of which has length of a side 6 cm.(plz, help me

)

1 answer:

harkovskaia [24]3 years ago

6 0

Answer:

216 cm3

Step-by-step explanation:

Prism is one of the shapes that I have never done before but I will try)

6 x 6 x 6 = 216cm3

Formula:

Length x Width x Height

Since every side of a cube have is the same cm or whatever, the height, width and height have the same numerals.

You might be interested in

Is my answer right to this problem

VLD [36.1K]

Yes it’s right for this problem

7 0

2 years ago

What is 6 tens x 10=

Effectus [21]

6 tens is the same as 60 so....
60 x 10 = 600

5 0

3 years ago

what is the common ratio for the geometric sequence below, written as a fraction? 768, 480, 300, 187.5, …

Crazy boy [7]

Let

$a1=768\\a2=480\\a3=300\\a4=187.5$

Step $1$

Find $\frac{a2}{a1}$

$\frac{a2}{a1} =\frac{480}{768}$

Divide by $96$ numerator and denominator

$\frac{480}{768} =\frac{\frac{480}{96}}{\frac{768}{96}} \\ \\ \frac{480}{768}=\frac{5}{8}$

$a2=a1*\frac{5}{8}$

Step $2$

Find $\frac{a3}{a2}$

$\frac{a3}{a2} =\frac{300}{480}$

Divide by $60$ numerator and denominator

$\frac{300}{480} =\frac{\frac{300}{60}}{\frac{480}{60}} \\ \\ \frac{300}{480}=\frac{5}{8}$

$a3=a2*\frac{5}{8}$

Step $3$

Find $\frac{a4}{a3}$

$a4=187.5 \\ a4=187\frac{1}{2} \\ \\ a4=\frac{375}{2}$

$\frac{a4}{a3} =\frac{\frac{375}{2}}{300} \\ \\ \frac{a4}{a3} =\frac{375}{600}$

Divide by $75$ numerator and denominator

$\frac{375}{600} =\frac{\frac{375}{75}}{\frac{600}{75}} \\ \\ \frac{375}{600}=\frac{5}{8}$

$a4=a3*\frac{5}{8}$

In this problem

The geometric sequence formula is equal to

$a(n+1)=a(n)*\frac{5}{8}\\$

For $n\geq 1$

therefore

the answer is

the common ratio for the geometric sequence above is $\frac{5}{8}$

6 0

3 years ago

Read 2 more answers

Last question! Please show work. Really need to get this done in 1 hour

Sav [38]

Answer:

x=1; y=2; z=3

Step-by-step explanation:

Rearrange for convince:

2y-4z+6x = -2

-4y+2z-3x=-5

-6y+3z+4x=1

Now we take to pairs and eliminate the same var.:

2y-4z+6x = -2 *2

-4y+2z-3x=-5

and

-4y+2z-3x=-5 *-3

-6y+3z+4x=1. *2

We get:

4y-8z+12y=-4

-4y+2z-3x=-5

= -6z+9x=-9

and

12y-6x+9x=15

-12y+6x+8x=2

= 17x=17

We now know x = 1, so z is:

-6z+9=-9

-6z=-18

z=3

Let’s grab the first formula and find y:

6+2y-12=-2

6+2y=10

2y=4

y = 2

7 0

2 years ago

What is the ratio of the intensities of an earthquake PP wave passing through the Earth and detected at two points 19 kmkm and 4

Tamiku [17]

Answer:

The ratio of the intensities is roughly 6:1.

Step-by-step explanation:

The intensity I() of an earthquake wave is given by:

$I = \frac{P}{4\pi d^{2}}$

<em>where P: is the power ans d: is the distance. </em>

Hence, the ratio of the intensities of an earthquake wave passing through the Earth and detected at two points 19 km and 46 km from the source is:

$\frac{I_{1}}{I_{2}} = \frac{P/4\pi d_{1}^{2}}{P/4\pi d_{2}^{2}}$

<em>where I₁ = P/4πd₁², d₁=19 km, I₁ = P/4πd₂² and d₂=46 km </em>

$\frac{I_{1}}{I_{2}} = \frac{d_{2}^{2}}{d_{1}^{2}}$

$\frac{I_{1}}{I_{2}} = \frac{46 km^{2}}{19 km^{2}}$

$\frac{I_{1}}{I_{2}} = 5.9:1$

Therefore, the ratio of the intensities is roughly 6:1.

I hope it helps you!

3 0

3 years ago