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2 years ago

Pleaseeee helppp meee!!!!

Mathematics

2 answers:

Nostrana [21]2 years ago

7 0

Answer:

4(9a - 4)

Step-by-step explanation:

36a - 16

take common

here 4 is the highest number which can divide noth 36 and 16 exactly

4(9a - 4)

rusak2 [61]2 years ago

6 0

Answer: 4(9a - 4)
Hope this helps

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Viktor [21]

Answer:

1) D

2) D

Step-by-step explanation:

1. Use 360 - x˚ - y˚ - 117˚ - 62˚

2. Recognize that 1) can be either 62 or 63

3. Plug either number into x to get y

4. y = 118 when x = 63

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2 years ago

How many pounds does 6.5 dozen cupcakes weigh?<br> • 1 cupcake = 35.3 grams

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2 years ago

Help totally lost plz help due today

ch4aika [34]

Answer:

5. 1

6. Kari is not correct.

Step-by-step explanation:

5. All like terms can be combined. There will be one term remaining after they are.

___

6. The appropriate factoring is x(x+1). This is not the same as x(2x+1).

In order to show equivalence, you need to show that the expressions produce the same result for as many different values of x as the degree of the expression plus 1. That is, you'd need to show equivalence for <em>3 different values of x</em>, as a minimum for this second-degree expression.

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3 years ago

Solve the following ODE's: c) y* - 9y' + 18y = t^2

Nastasia [14]

Answer:

y = $C_1e^{3t}+C_2e^{6t}$ + $\dfrac{1}{18}(t^2+\frac{2t}{6} + \frac{2}{36}+\frac{2t}{3}+\frac{2}{18}+\frac{2}{9})$

Step-by-step explanation:

y''- 9 y' + 18 y = t²

solution of ordinary differential equation

using characteristics equation

m² - 9 m + 18 = 0

m² - 3 m - 6 m+ 18 = 0

(m-3)(m-6) = 0

m = 3,6

C.F. = $C_1e^{3t}+C_2e^{6t}$

now calculating P.I.

$P.I. = \frac{t^2}{D^2 - 9D +18}$

$P.I. = \dfrac{t^2}{(D-3)(D-6)}\\P.I. =\dfrac{1}{18}(1-\frac{D}{3})^{-1}(1-\frac{D}{6})^{-1}(t^2)\\P.I. =\dfrac{1}{18}(1-\frac{D}{3})^{-1}(1+\frac{D}{6}+\frac{D^2}{36}+....)(t^2)\\P.I. =\dfrac{1}{18}(1-\frac{D}{3})^{-1}(t^2+\frac{2t}{6} + \frac{2}{36})\\P.I. =\dfrac{1}{18}(1+\frac{D}{3}+\frac{D^2}{9}+....)(t^2+\frac{2t}{6} + \frac{2}{36})\\P.I. =\dfrac{1}{18}(t^2+\frac{2t}{6} + \frac{2}{36}+\frac{2t}{3}+\frac{2}{18}+\frac{2}{9})$

hence the complete solution

y = C.F. + P.I.

y = $C_1e^{3t}+C_2e^{6t}$ + $\dfrac{1}{18}(t^2+\frac{2t}{6} + \frac{2}{36}+\frac{2t}{3}+\frac{2}{18}+\frac{2}{9})$

7 0

2 years ago

If f(x) = -x + 8 and g(x) = x^4, what is (gºf)(2)?

kotykmax [81]

Answer:

$\large\boxed{(g\circ f)(2)=1296}$

Step-by-step explanation:

$(g\circ f)(x)=g\bigg(f(x)\bigg)\\\\f(x)=-x+8,\ g(x)=x^4\\\\(g\circ f)(x)=\g\bigg(f(x)\bigg)=(-x+8)^4\\\\(g\circ f)(2)\to\text{put x = 2 to the equation}\ (g\circ f)(x):\\\\(g\circ f)(2)=(-2+8)^4=(6)^4=1296$

7 0

2 years ago

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