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natita [175]
3 years ago
10

What is the equivalent fractions for 20/50 and 3/11?

Mathematics
1 answer:
yaroslaw [1]3 years ago
6 0
Equivalent fractions for 20/50 => <span>2/5, 4/10, 6/15,and so on .....
=> 20/50 = 2/5 
=> 20/50*2 = 4/10
=> 20/50*3 = 6/15

</span>equivalent fractions for 3/11 => <span>3/11, 6/22, 9/33, 12/44 and so on ...
=> 3/11* 2 = 6/22
=> 3/11* 3 = 9/33
=> 3/11* 4 = 12/44

Hope it helps !!!
</span>

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Find the measure of an angle whose measure is 20° less than the measure of its supplement.
Tasya [4]
Supplementary = angles add up to 180
Measure = 20 less

Labelled as x + (x - 20) = 180

Solve.

x + (x - 20) = 180
             2x = 200
             /2      /2
               x = 100

Angle 1:             Angle 2:
x - 20                  x
100 - 20             100
80

Therefore the angle is 80 degrees.

Proof: 80 + 100 = 180 (supplementary)
100 - 80 = 20 (80 is less than supplement (100)

Hope I helped :))))
3 0
3 years ago
Four friends earned $5.20 for washing a car. They shared the money equally. How much did each friend get?
horsena [70]
Each friend got $1.30 I hope this helps!!!!
5 0
3 years ago
Read 2 more answers
PLEASE HELP I WILL GOVE BRAINLIEST
vaieri [72.5K]
Y - 3 = -2(x+5)
y - 3 = -2x - 10
+3. +3
y = -2x - 7
3 0
3 years ago
Find the inverse f(x)=6x+7
Lorico [155]

Answer:

f^{-1} (x) = \frac{x-7}{6}

Step-by-step explanation:

let y = f(x) , then rearrange making x the subject

y = 6x + 7 ( subtract 7 from both sides )

y - 7 = 6x ( divide both sides by 6 )

\frac{y-7}{6} = x

Change y back into terms of x with x = f^{-1} (x) , then

f^{-1} (x) = \frac{x-7}{6}

7 0
2 years ago
Pentagon ABCDE and pentagon A″B″C″D″E″ are shown on the coordinate plane below:
erastova [34]

The transformations that are applied to pentagon ABCDE to create A"B"C"D"E" are:

1) Translation (x, y) → (x + 8, y + 2)

2) Reflection across the x-axis (x, y) → (x, -y)

So, the overall transformation given in the graph is (x, y) → {(x + 8), -(y + 2)}.

<h3>What are the transformation rules?</h3>

The transformation rules are:

  • Reflection across x-axis: (x, y) → (x, -y)
  • Reflection across y-axis: (x, y) → (-x, y)
  • Translation: (x, y) → (x + a, y + b)
  • Dilation: (x, y) → (kx, ky)

<h3>Calculation:</h3>

The pentagons in the graph have vertices as

For the pentagon ABCDE: A(-4, 5), B(-6, 4), C(-5, 1), D(-2, 2), and (-2, 4)

For the pentagon A"B"C"D"E": A"(4, -7), B"(2, -6), C"(3, -3), D"(6, -4), and E"(6, -6)

Consider the vertices A(-4, 5) from the pentagon ABCDE and A"(4, -7) from the pentagon A"B"C"D"E".

Applying the Translation rule for the pentagon ABCDE:

The rule is (x, y) → (x + a, y + b)

So, the variation is

-4 + a = 4

⇒ a = 4 + 4 = 8

5 + b = 7

⇒ b = 7 - 5 = 2

So, the pentagon ABCDE is translated by (x + 8, y + 2).

Applying the Reflection rule for the translated pentagon:

The translated pentagon has vertices (x + 8, y + 2).

When applying the reflection across the x-axis,

(x + 8, y + 2) → {(x + 8), -(y + 2)}

Therefore, the complete transformation of the pentagon ABCDE to the pentagon A"B"C"D"E" is (x, y) → {(x + 8), -(y + 2)}

Verification:

A(-4, 5) → ((-4 + 8), -(5 + 2)) = (4, -7)A"

B(-6, 4) → ((-6 + 8), -(4 + 2)) = (2, -6)B"

C(-5, 1) → ((-5 + 8), -(1 + 2)) = (3, -3)C"

D(-2, 2) → ((-2 + 8), -(2 + 2)) = (6, -4)D"

E(-2, 4) → ((-2 + 8), -(4 + 2)) = (6, -6)E"

Learn more about transformation rules here:

brainly.com/question/4289712

#SPJ1

5 0
1 year ago
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