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gtnhenbr [62]
2 years ago
15

This is worth 20 points, please answer! (Also, please answer with a variable in the equation.) Sorry about the quality!

Mathematics
2 answers:
algol [13]2 years ago
6 0
Answer : 362+54=m+416
m=cost after 1 month
pshichka [43]2 years ago
5 0

Answer:

362+54=416+m    m=cost after month 1

Step-by-step explanation:

You might be interested in
The baker at weis supermarket will cut 5 indeticial loaves of bread into pices that are 1/3 . After he cuts the 5 loaves how man
IrinaK [193]

Answer:

15 pieces

Step-by-step explanation:

we see if we get 3 pieces from one bread then 5 will be 15

hope it helps you

please mark me as brainlist

5 0
3 years ago
Read 2 more answers
-2(bx - 5) = 16<br><br> What’s does b and x equal?
horrorfan [7]
To solve this problem you must apply the proccedure shown below:
 You have the following equation given in the problem above:
 <span>-2(bx - 5) = 16
</span> When you solve for bx, you have:
 <span>-2(bx - 5) = 16
 -2bx-10=16
 -2bx=26
 bx=26/-2
 bx=-13

 When you solve for b, you obtain:
 </span><span>-2(bx - 5) = 16
 -2bx=26
 b=-(26/2x)

 When yoo solve for x:
 </span>2bx=26
 x=-(26/2b)<span>

 </span>
3 0
3 years ago
If B=3x^{2}-x+3 and A=x-6, find an expression that equals 2B+3A in standard form.
Ivan

9514 1404 393

Answer:

  6x^2 +x -12

Step-by-step explanation:

Substitute for A and B and collect terms.

  2B +3A

  = 2(3x^2 -x +3) +3(x -6) . . . . substitute for A and B

  = 6x^2 -2x +6 +3x -18 . . . . . eliminate parentheses

  = 6x^2 +x -12 . . . . . . . . . . . . collect terms

7 0
3 years ago
Each of 16 students measured the circumference of a tennis ball by four different methods, which were: A: Estimate the circumfer
almond37 [142]

Answer:

Following are the solution to the given equation:

Step-by-step explanation:

Please find the complete question in the attachment file.

In point a:

\to \mu=\frac{\sum xi}{n}

       =22.8

\to \sigma=\sqrt{\frac{\sum (xi-\mu)^2}{n-1}}

       =\sqrt{\frac{119.18}{16-1}}\\\\ =\sqrt{\frac{119.18}{15}}\\\\ = \sqrt{7.94533333}\\\\=2.8187

In point b:

\to \mu=\frac{\sum xi}{n}

       =20.6875  

\to \sigma=\sqrt{\frac{\sum (xi-\mu)^2}{n-1}}

       =\sqrt{\frac{26.3375}{16-1}}\\\\=\sqrt{\frac{26.3375}{15}}\\\\ =\sqrt{1.75583333}\\\\ =1.3251

In point c:

 \to \mu=\frac{\sum xi}{n}

         =21  

\to \sigma=\sqrt{\frac{\sum (xi-\mu)^2}{n-1}}

       =\sqrt{\frac{2.62}{16-1}}\\\\ =\sqrt{\frac{2.62}{15}} \\\\= \sqrt{0.174666667}\\\\=0.4179

In point d:

\to \mu=\frac{\sum xi}{n}

       =20.8375  

\to \sigma=\sqrt{\frac{\sum (xi-\mu)^2}{n-1}}

       =\sqrt{\frac{8.2975}{16-1}}\\\\ =\sqrt{\frac{8.2975}{15}} \\\\  =\sqrt{0.553166667} \\\\ =0.7438

6 0
3 years ago
Plz help need to graduate​
lutik1710 [3]

It's most likely the first or 3rd answer. Apologies If I'm wrong.

3 0
3 years ago
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