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3 years ago

1. Suppose the length of each side of a square is increased by 5 feet. If the perimeter of

Mathematics

1 answer:

Temka [501]3 years ago

3 0

The answer is either B. or C.

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(10) Both red line and blue line trains left the station at 5:00 pm. If both

scoundrel [369]

Answer:

5:40

Step-by-step explanation:

This is a problem involving the least common difference.

If you know that the red and blue trains left at the same time at 5, you know that another red train will leave at 5:08. Another blue train at 5:10.

The way to solve this will be to write out the factors of 8 and 10 and find the smallest number that they overlap.

Red:

8, 16, 24, 32, 40, 48, 56, 64, 72, 80

Blue:

10, 20, 30, 40

You see that after 40 mnutes, they are both leaving the station again. After 40 minutes, at 5:40, they are both leaving.

6 0

3 years ago

If a quadratic function has x-intercepts at (-7,0) and 10,0), where would

madam [21]

Answer:

x = 1.5

Step-by-step explanation:

Since the axis of symmetry is between the 2 x intercepts, we can find it by finding the average of the x-coordinates of the 2 points.

(-7 + 10) / 2

3/2

= 1.5

So, the axis of symmetry is at x = 1.5

8 0

3 years ago

claire has 250 pennies. Some are in a box and some are in her bank. There are more than 100 pennies in each place. How many penn

BartSMP [9]

125 is the correct answer yup yupp

6 0

3 years ago

Read 2 more answers

The measure of EFH is twice the measure of GFH. What is the

Vladimir [108]

Answer:

30° = m∠GFH

Step-by-step explanation:

Since ∠EFH and ∠GFH are complementary, the sum of their measures i 90.

Let x = m∠GFH

2x = m∠EFH

m∠GFH + m∠EFH = 90

x + 2x = 90

3x = 90

x = 30° = m∠GFH

8 0

3 years ago

In an examination given to a class of 20 students, the following test scores were obtained.

nexus9112 [7]

Answer:

Mean = 75

Median = 80

Mode = 85

The mode

Step-by-step explanation:

Given the data :

45 45 50 50 55 60 70 75 75 80 80 85 85 85 85 90 95 95 95 100

Rearranged data :

45, 45, 50, 50, 55, 60, 70, 75, 75, 80, 80, 85, 85, 85, 85, 90, 95, 95, 95, 100

The mean score :

ΣX / n ; n = sample size = 20

ΣX = 1500

Mean = 1500 / 20 = 75

Mode = most frequently occurring = 85 ( frequency of 4)

Median = 0.5(n + 1)th term

Median = 0.5(20 + 1)th term

Median = 0.5(21) th term

Median = 10.5th term = (10 + 11)th term / 2

Median = (80 + 80) / 2 = 160 / 2 = 80

2.) The mode

4 0

3 years ago