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Mashutka [201]
3 years ago
12

If an object has a Mass of 11g and a volume fo 13mil, what is its density?

Mathematics
2 answers:
denis23 [38]3 years ago
6 0

Answer:

B

Step-by-step explanation:

tino4ka555 [31]3 years ago
5 0

Step-by-step explanation:

Mass (m) = 11 g

volume (v) = 13 ml

density (d) = ?

We know density is defined as mass per unit volume so

d = m / v

= 11 / 13

= 0.85 g/ml

Density (d) = 0.85 g/ml

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Solve this right now for a billion dollars
Tema [17]

Answer:

Step-by-step explanation:

Simplifying

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Reorder the terms:

-5.7 + 2.1x = 3.9(4.3 + -1.8x)

-5.7 + 2.1x = (4.3 * 3.9 + -1.8x * 3.9)

-5.7 + 2.1x = (16.77 + -7.02x)

Solving

-5.7 + 2.1x = 16.77 + -7.02x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '7.02x' to each side of the equation.

-5.7 + 2.1x + 7.02x = 16.77 + -7.02x + 7.02x

Combine like terms: 2.1x + 7.02x = 9.12x

-5.7 + 9.12x = 16.77 + -7.02x + 7.02x

Combine like terms: -7.02x + 7.02x = 0.00

-5.7 + 9.12x = 16.77 + 0.00

-5.7 + 9.12x = 16.77

Add '5.7' to each side of the equation.

-5.7 + 5.7 + 9.12x = 16.77 + 5.7

Combine like terms: -5.7 + 5.7 = 0.0

0.0 + 9.12x = 16.77 + 5.7

9.12x = 16.77 + 5.7

Combine like terms: 16.77 + 5.7 = 22.47

9.12x = 22.47

Divide each side by '9.12'.

x = 2.463815789

Simplifying

x = 2.463815789

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Answer:

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Step-by-step explanation:

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10 = \frac{30k}{6} ( multiply both sides by 6 )

60 = 30k ( divide both sides by 30 )

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The family of functions y = ce^{-2x} + e^{-x} is solution of the equation y' + 2y = e^{-x}. Find the constant c which defines th
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Answer:

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Step-by-step explanation:

We have the following solution:

y(x) = ce^{-2x} + e^{-x}

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c = \frac{2.9502}{e^{-6}}

c = 1190.2

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2 years ago
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