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3 years ago

If an object has a Mass of 11g and a volume fo 13mil, what is its density?

Mathematics

2 answers:

denis23 [38]3 years ago

6 0

Answer:

Step-by-step explanation:

tino4ka555 [31]3 years ago

5 0

Step-by-step explanation:

Mass (m) = 11 g

volume (v) = 13 ml

density (d) = ?

We know density is defined as mass per unit volume so

d = m / v

= 11 / 13

= 0.85 g/ml

Density (d) = 0.85 g/ml

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Given:

The sequence is:

$17,-\dfrac{17}{8},\dfrac{17}{27},-\dfrac{17}{64},\dfrac{17}{125},...$

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The formula for the nth term in the given sequence.

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3 years ago

The U.S. Energy Information Administration (US EIA) reported that the average price for a gallon of regular gasoline is . The US

alexandr1967 [171]

Answer:

The answer is "23, 62, and 139"

Step-by-step explanation:

In point a:

$\to \sigma = \$0.24\\\\ \to E = \$0.10\\\\ 95\% \text{confidence level of the z}: \\\\\to \alpha = 1 - 95\% = 1 - 0.95 = 0.05\\\\\to \frac{\alpha}{2} = \frac{0.05}{2} = 0.025\\\\\to Z_{\frac{\alpha}{2}} = Z_{0.025} = 1.96\\\\$

Calculating the sample size:

$\to n = (\frac{(Z_{\frac{\alpha}{2}} \times \sigma)}{E})^2$

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In point b:

$\to \sigma = \$0.24\\\\\to E = \$0.06\\\\\to Z_{\frac{\alpha}{2}} = Z_{0.025} = 1.96\\\\\to n = (\frac{(Z_{\frac{\alpha}{2}} \times \sigma )}{E})^2\\\\$

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$\to \sigma = \$0.24\\\\\to E =\$0.04\\\\\to Z_{\frac{\alpha}{2}} = Z_{0.025} = 1.96\\\\\to n = (\frac{(Z_{\frac{\alpha}{2}} \times \sigma )}{E})^2\\\\$

$= (\frac{(1.96\times 0.24 )}{0.04})^2 \\\\=138.30 \approx 139$

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