the probability that if you pick only one, it's defective, is 250/6700
Therefore, the probability that one is not defective is 6450/6700
a. You want all 4 to not be defective: (6450/6700)^4
b. all 100 have to be not defective: (6450/6700)^100
If you type this into a calculator, you will get about 0.022, so a probability of 2 % that all of them are not defective. As this is a very small probability, the outlet should plan with returned tires.
Answer:
It is B
Step-by-step explanation:
Because you divided 1÷3 and you get 0.3333333333
Answer:
14.14
Step-by-step explanation:
V=4
3πr3=4
3·π·1.53≈14.13717
-3+11p
first you add 1+2p that gets you -3 then you do 9p-4 and you get 11p from there you can either solve it, or leave it as is, depending on what your teacher wants.
Let x= the number of books purchased: 7 books purchased
let y = the number of toys purchased;10 toys purchased
Equations: x+y=17
6x+11y=152 x+10=17
-6(x+y=17) y=10 -10 -10
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-6x-6y=-102 x=7
6x+11y=152
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0x+5y=50
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5 5
