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Irina18 [472]
2 years ago
14

Can you write down the days of the week with the number "500" next to them for me. Make this 2 times thank you :)

Mathematics
2 answers:
zmey [24]2 years ago
6 0

Answer:

500 monday     500 monday

500 thuesday   500 thuesday

500 wenday     500 wenday

500 thusday     500 thusday

500 friday         500 friday

Step-by-step explanation:

pls mark brainliest

Triss [41]2 years ago
5 0

Answer:

my day is going very sad so please sir l am try to improve my self help me

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3 7/24 is the answer for your question
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The numbers of beads on 500 handcrafted bead
pashok25 [27]
 <span>The numbers of beads on 500 handcrafted bead necklaces follow a normal distribution whose mean is 24 beads and standard deviation is 4 beads. 
</span>so....
<span>About 24 necklaces have more than 28 beads. </span>
<span>About 48 necklaces have more than 28 beads. </span>
<span>About 80 necklaces have more than 28 beads. </span>
About 96 necklaces have more than 28 beads<span>

</span> <span>About 80 necklaces have more than 28 beads. 
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Z score is 28-24/4=1 
(1-.8413)=0.1587 

500*0.1587=79.35~80

i did this like 2 or 3 years ago .</span>
7 0
2 years ago
Gemma had 25.75 grams of frosting to make a cake. She decided to use only 15.5 grams of the frosting. How much frosting does Gem
Finger [1]

Answer:

  • 10.2 grams

Step-by-step explanation:

Gemma had 25.75 grams of frosting

Used 15.5 grams

<u>Left over:</u>

  • 25.75 - 15.5 = 10.2 grams
8 0
3 years ago
The solution to a quadric equation are x=2 and x=7. If k is a nonzero constant which of the following must be equal to the quadr
nikklg [1K]

Answer:

The quadratic equation form is x² - 9 x + 14  = 0            

Step-by-step explanation:

Given in the question as ,

The solution of quadratic equation are x = 2   and x = 7

The constant K is a non-zero number

Now , let the quadratic equation be , ax² + bx + c = 0

And  sum of roots = \frac{ - b}{a}

       product of roots = \frac{c}{a}

So, 2 + 7 = \frac{ - b}{a}

Or, 2 × 7 =  \frac{c}{a}

I.e \frac{ - b}{a}  = 9     ,     \frac{c}{a} = 14

Or,  b =  - 9 a           And c = 14 a

Put this value of b and c in standard form of quadratic equation

I.e ax² + bx + c = 0

Or, ax² - 9 ax + 14 a = 0

Or , a ( x² - 9 x + 14 ) = 0  

∴ a = 0   And  x² - 9 x + 14 = 0

Hence ,  The quadratic equation form is x² - 9 x + 14  = 0      Answer

7 0
3 years ago
What’s the answer to this? I need to do this for extra credit and I have no idea what this is
sergiy2304 [10]

9514 1404 393

Answer:

  20

Step-by-step explanation:

As with any evaluation problem, take it step by step according to the order of operations.

The first thing you need to do here is compute a#b.

The given definition can be simplified a bit for evaluation purposes:

  a#b = a²b -ab² = ab(a -b)

Then for a=3 and b=-2, you have ...

  (3)#(-2) = (3)(-2)(3 -(-2)) = -6(5) = -30

Now, you are in a position to evaluate the expression you're asked for.

  \dfrac{(a\#b)^2}{15-(a\#b)}=\dfrac{(-30)^2}{15-(-30)}=\dfrac{900}{45}=\boxed{20}

4 0
3 years ago
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