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Natali [406]
2 years ago
13

Raina, Alan, and Kareem have a total of $85 in their wallets. Kareem has $9 less than Raina. Alan has 2 times what Kareem has. H

ow
much do they have in their wallets?
Amount in Raina's wallet
$
Amount in Alan's wallet:
$
Amount in Kareem's wallet:
$

Mathematics
1 answer:
Klio2033 [76]2 years ago
5 0

Answer:

17,  51,  24.

Step-by-step explanation:

i cant type it rn but i will put it in comments later :D hope this helped!

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Can you please help please please help me with this question is so hard and i will give you a Brainiest please
mrs_skeptik [129]

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x ≤ 4

Question 2:

i think its 40-5

7 0
2 years ago
In this square, all the angles are equal. What is the measure of angle x°?
Kisachek [45]

Answer:

90

Step-by-step explanation:

8 0
2 years ago
(08.01 LC)
skad [1K]

Answer:

all students on the track-and-field team

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5 0
2 years ago
Steve and Abby purchased a set of vases to place on a 12 foot long mantel above their fireplace. They want to place one vase 1/4
Nonamiya [84]

Answer: One vase should be placed 3 feet from the end of the mantel and the other vase should be placed 9 feet from the same end.

Step-by-step explanation:

You know that lenght of the mantel above their fireplace is 12 feet.

They want to place one vase \frac{1}{4} of the distance from one end of the mantel. This distance in feet is:

distance_{vase1}=(12feet)(\frac{1}{4})\\\\distance_{vase1}=3feet

 They want to place the other vase \frac{3}{4} of the distance from the same end of the mantel. Therefore, this distance in feet is:

distance_{vase2}=(12feet)(\frac{3}{4})\\\\distance_{vase2}=\frac{36feet}{4}\\\\distance_{vase2}=9feet

Therefore, one vase should be placed 3 feet from the end of the mantel and the other vase should be placed 9 feet from the same end.

5 0
3 years ago
Find all real solutions of the equation. <br> x4/3 − 7x2/3 + 10 = 0
BlackZzzverrR [31]
Solve by Factoring x^(2/3)-7x^(1/3)+10=0
x
2
3
−
7
x
1
3
+
10
=
0
x
2
3
-
7
x
1
3
+
10
=
0
Rewrite
x
2
3
x
2
3
as
(
x
1
3
)
2
(
x
1
3
)
2
.
(
x
1
3
)
2
−
7
x
1
3
+
10
=
0
(
x
1
3
)
2
-
7
x
1
3
+
10
=
0
Let
u
=
x
1
3
u
=
x
1
3
. Substitute
u
u
for all occurrences of
x
1
3
x
1
3
.
u
2
−
7
u
+
10
=
0
8 0
3 years ago
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