The given expression :

For coordinates:
put x = 0 then :

Coordinate : (x, y) = (0, 1)
Put x= 1 and simplify :

Coordinate : (x, y) = ( 1, 0.5)
Put x = (-2) and simplify :

Coordinate : (x, y) = ( -2, 4)
Put x = (-3) and simplify :

Coordinate : (x, y) = (-3, 8)
Substitute x = (-1) and simplify :

Coordinate : (x, y) = ( -1, 2)
So, the coordinates are :
The graph is :
Answer:
62.4 square centimeters
Step-by-step explanation:
The picture of the question in the attached figure
we know that
The surface area of the triangular pyramid is equal to the area of the triangular base plus the area of its three lateral triangular faces
In this problem the triangles are equilateral, that means, the
surface area is equal to the area of four congruent equilateral triangles
so
![A=4[\frac{1}{2}(b)(h)]](https://tex.z-dn.net/?f=A%3D4%5B%5Cfrac%7B1%7D%7B2%7D%28b%29%28h%29%5D)
we have

substitute
![A=4[\frac{1}{2}(6)(5.2)]=62.4\ cm^2](https://tex.z-dn.net/?f=A%3D4%5B%5Cfrac%7B1%7D%7B2%7D%286%29%285.2%29%5D%3D62.4%5C%20cm%5E2)
Answer:
$190.00
Step-by-step explanation:
285÷30=9.5
9.5×20=190
Hope this helps! :)
The area is 2,772 feet
Hope this helps! Good luck on your homework!!!
Vcyl = Vcone
pi×x^2×y = 1/3×pi×(3x)^2 (h)
pi's cancel--> x^2•y = 3x^2 (h)
h = y/3