Answer:
a) 95% of the widget weights lie between 29 and 57 ounces.
b) What percentage of the widget weights lie between 12 and 57 ounces? about 97.5%
c) What percentage of the widget weights lie above 30? about 97.5%
Step-by-step explanation:
The empirical rule for a mean of 43 and a standard deviation of 7 is shown below.
a) 29 represents two standard deviations below the mean, and 57 represents two standard deviations above the mean, so, 95% of the widget weights lie between 29 and 57 ounces.
b) 22 represents three standard deviations below the mean, and the percentage of the widget weights below 22 is only 0.15%. We can say that the percentage of widget weights below 12 is about 0. Equivalently we can say that the percentage of widget weights between 12 an 43 is about 50% and the percentage of widget weights between 43 and 57 is 47.5%. Therefore, the percentage of the widget weights that lie between 12 and 57 ounces is about 97.5%
c) The percentage of widget weights that lie above 29 is 47.5% + 50% = 97.5%. We can consider that the percentage of the widget weights that lie above 30 is about 97.5%
(6•x) + 7 = 8
6x + 7 = 8
6x = 1
X = 1
X is 7 obiviously because when you subtract 5 from both sides you are gonna have 7 for x
Answer:
H0: μ ≤ 34
H1: μ > 34
The z-test statistic is ≈ 1.8
The critical z-score is 1.28
we fail to reject the null hypothesis H0: μ ≤ 34
Step-by-step explanation:
H0: μ ≤ 34
H1: μ > 34
The z-test statistic is calculated using the formula:
z=
where
- X is the average class size found in the sample (35.6)
- M is the mean according to the null hypothesis (34)
- s is the standard deviation for class size (9)
then z=
≈ 0.18
The critical z-score is 1.28 for α=0.10 (one tailed)
Because the test statistic is less than the critical value, do not reject the null hypothesis.