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NARA [144]
4 years ago
15

Find the slope in (5,1) and (-2,1)

Mathematics
2 answers:
xeze [42]4 years ago
8 0

Use the slope formula: \frac{y_2-y_1}{x_2-x_1}. Substitute the appropriate coordinates into the formula.

y_2 = 1

y_1 = 1

x_2 = -2

x_1 = 5

\frac{1-1}{-2-5} = \frac{0}{-7} =0. The slope is 0.

Elden [556K]4 years ago
5 0
Use the slope formula
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What is the coefficient of the term 13a in the expression 13a+6b? Please Help Fast alot of points
KATRIN_1 [288]

Answer:

13

Step-by-step explanation:

A coefficient is the contestant value (a number) placed before a variable to be multiplied. A coefficient is multiplied by it's neighboring variable. In '13a', 13 is being multiplied by a.

13 will be the coefficient in 13a.

3 0
3 years ago
find the equation of the line passing through the given point and perpendicular to the given equation write your answer in slope
Paraphin [41]

Slope-intercept form:

y = mx + b      "m" is the slope, "b" is the y-intercept


For lines to be perpendicular, their slopes have to be the opposite/negative reciprocals (flipped sign and number)

For example:

slope is 2

perpendicular line's slope is -1/2

slope is -2/3

perpendicular line's slope is 3/2



3.) y = 2x - 2

The given line's slope is 2, so the perpendicular line's slope is -1/2

y=-\frac{1}{2}x+b To find "b", plug in the point (-5 , 5) into the equation

5=-\frac{1}{2}(-5)+b

5=\frac{5}{2}+b     Subtract 5/2 on both sides

5-\frac{5}{2}=b   Make the denominators the same

\frac{10}{2}-\frac{5}{2}=b

\frac{5}{2}=b


y=-\frac{1}{2}x+\frac{5}{2}



4.) -6x + 5y = -10     Get "y" by itself, add 6x on both sides

5y = -10 + 6x          Divide 5 on both sides

y=-2+\frac{6}{5}x

The given line's slope is 6/5, so the perpendicular line's slope is -5/6.

y=-\frac{5}{6}x+b       Plug in (-2, 5)

5 = -\frac{5}{6}(-2)+b

5=\frac{10}{6}+b\\ 5=\frac{5}{3}+b    Subtract 5/3 on both sides

5-\frac{5}{3} =b    Make the denominators the same

\frac{15}{3}-\frac{5}{3}=b\\\frac{10}{3} =b


y = -\frac{5}{6}x+\frac{10}{3}



7.) Perpendicular line's slope is -2

y = -2x + b      Plug in (1,4)

4 = -2(1) + b

4 = -2 + b

6 = b


y = -2x + 6



8.) Perpendicular line's slope is -1/4

y = -\frac{1}{4}x+b     Plug in (-5 , 2)

2=-\frac{1}{4}(-5)+b

2 = \frac{5}{4}+b    Subtract 5/4 on both sides

2-\frac{5}{4}=b     Make the denominators the same

\frac{8}{4}-\frac{5}{4}=b

\frac{3}{4}=b


y=-\frac{1}{4}x+\frac{3}{4}

5 0
3 years ago
3 2/6 + ( 2 1/6 + 4/6 )
stellarik [79]

Answer:

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3 0
4 years ago
The diagram shows a sector of a circle radius 10cm. Find the perimeter of the sector, giving your answer correct to 1 decimal pl
qwelly [4]
<h2>Explanation:</h2><h2></h2>

Hello! Remember you have to write complete questions in order to get good and exact answers. Anyway, I'll help you either way. A sector is a region of a circle between two radii. Let's assume the sector as:

s=25\pi cm^2

Then, we can find the central angle by the following equation:

s=\frac{\theta}{360}\times\pi r^{2} \\ \\ r=10cm \\ \\ s=25\pi cm^2 \\ \\ \\ So: \\ \\ \frac{25\pi(360)}{10^2\pi}=\theta \\ \\ \theta = 90^{\circ}

But:

90^{\circ}=\frac{\pi}{2}

Then:

C:Perimeter \ of \ sector \\ \\ \\ C=\theta r \\ \\ C=\frac{\pi}{2}(10) \\ \\ C=5\pi cm \approx \boxed{15.7cm}

6 0
4 years ago
Decide if this statement is<br> true or false.<br> x = 2 if and only if | x1 = 2<br> A.true B. False
diamong [38]

Answer:

true, do u need an explanation?

6 0
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