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NARA [144]
3 years ago
15

Find the slope in (5,1) and (-2,1)

Mathematics
2 answers:
xeze [42]3 years ago
8 0

Use the slope formula: \frac{y_2-y_1}{x_2-x_1}. Substitute the appropriate coordinates into the formula.

y_2 = 1

y_1 = 1

x_2 = -2

x_1 = 5

\frac{1-1}{-2-5} = \frac{0}{-7} =0. The slope is 0.

Elden [556K]3 years ago
5 0
Use the slope formula
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Curtis wants to save money for a trip overseas. Curtis invests $900 in an account that pays an interest rate of 8.75%. How many
professor190 [17]
Hi there
The formula is
A=p (1+r)^t
A future value 11700
P present value 900
R interest rate 0.0875
T time?
We need to solve for t
T=log (A/p)÷log (1+r)
So
T=log(11,700÷900)÷log(1+0.0875)
T=30.6years round your answer to get
T=31 years

Hope it helps
7 0
3 years ago
Read 2 more answers
The population of an island is 6000 people this year and is projected to be 6300 people next year, by what percentage is the pop
Julli [10]

Answer:

5% increase

Step-by-step explanation:

First, find how much it increased:

6300 - 6000

= 300

Then, to find the percent increase, divide 300 by 6000

300/6000

= 0.05

So, there was a 5% increase in the population

8 0
3 years ago
If a day was a year, how many does it take to make a million years?
Tasya [4]
It would take 2,740 days to make a million years.

1,000,000 divided by 365.
6 0
3 years ago
Read 2 more answers
A ship leaves port at 10 miles per hour, with a heading of N 35° W. There is a warning buoy located 5 miles directly north of th
Leno4ka [110]

The value of the angle subtended by the distance of the buoy from the

port is given by sine and cosine rule.

  • The bearing of the buoy from the is approximately <u>307.35°</u>

Reasons:

Location from which the ship sails = Port

The speed of the ship = 10 mph

Direction of the ship = N35°W

Location of the warning buoy = 5 miles north of the port

Required: The bearing of the warning buoy from the ship after 7.5 hours.

Solution:

The distance travelled by the ship = 7.5 hours × 10 mph = 75 miles

By cosine rule, we have;

a² = b² + c² - 2·b·c·cos(A)

Where;

a = The distance between the ship and the buoy

b = The distance between the ship and the port = 75 miles

c = The distance between the buoy and the port = 5 miles

Angle ∠A = The angle between the ship and the buoy = The bearing of the ship = 35°

Which gives;

a = √(75² + 5² - 2 × 75 × 5 × cos(35°))

By sine rule, we have;

\displaystyle \frac{a}{sin(A)} = \mathbf{ \frac{b}{sin(B)}}

Therefore;

\displaystyle sin(B)= \frac{b \cdot sin(A)}{a}

Which gives;

\displaystyle sin(B) = \mathbf{\frac{75 \cdot sin(35^{\circ})}{\sqrt{75^2 + 5^2 - 2 \times 75\times5\times cos(35^{\circ}) } }}

\displaystyle B = arcsin\left( \frac{75 \cdot sin(35^{\circ})}{\sqrt{75^2 + 5^2 - 2 \times 75\times5\times cos(35^{\circ}) } }\right) \approx 37.32^{\circ}

Similarly, we can get;

\displaystyle B = arcsin\left( \frac{75 \cdot sin(35^{\circ})}{\sqrt{75^2 + 5^2 - 2 \times 75\times5\times cos(35^{\circ}) } }\right) \approx \mathbf{ 142.68^{\circ}}

The angle subtended by the distance of the buoy from the port, <em>C</em> is therefore;

C ≈ 180° - 142.68° - 35° ≈ 2.32°

By alternate interior angles, we have;

The bearing of the warning buoy as seen from the ship is therefore;

Bearing of buoy ≈ 270° + 35° + 2.32° ≈ <u>307.35°</u>

Learn more about bearing in mathematics here:

brainly.com/question/23427938

5 0
2 years ago
The polynomial below is perfect square trinomial of the form a^2 -2AB +B^2
guajiro [1.7K]

Answer:

In order to get this perfect square trinomial, the factored form will be (a - b)^2

Step-by-step explanation:

We know this because it follows the rule of perfect squares in which the ends are both squares and the middle term is -2 times each term.

5 0
3 years ago
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