Question

Whats is the distance between the ferris wheel and the merry-go-round? Ferris wheel on the coordinate plane is (-9,6) and the location of the merry-go-round is (10,6)

Answer 1

Answer:

19 units

Step-by-step explanation:

use distance formula: d = $\sqrt{(x_2-x_1)^{2}+(y_2+y_1)^{2}}$

x₂ = 10

x₁ = -1

y₂ = 6

y₁ = 6

now plug in

$\sqrt{(10-(-9))^{2}+(6-6)^{2}}\\= \sqrt{19^{2}+0^{2}\\}\\= \sqrt{361}\\= 19$