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2 years ago

5. A rectangle with a diagonal of length x is twice as long as it is wide. Find the area of the

Mathematics

1 answer:

ahrayia [7]2 years ago

8 0

Answer:

The awnser is C

Step-by-step explanation:

common sense cause 1/2 +1/2 = 2

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What is 1 and 2/5× 7

OleMash [197]

7/5 x 7/1 = 49/5 or 9 4/5

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3 years ago

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Expand (2x+2)^6<br> How would you find the answer using the binomial theorem?

Yanka [14]

Answer:

Step-by-step explanation:

$\displaystyle\\\sum\limits _{k=0}^n\frac{n!}{k!*(n-k)!}a^{n-k}b^k .\\\\k=0\\\frac{n!}{0!*(n-0)!}a^{n-0}b^0=C_n^0a^n*1=C_n^0a^n.\\\\ k=1\\\frac{n!}{1!*(n-1)!} a^{n-1}b^1=C_n^1a^{n-1}b^1.\\\\k=2\\\frac{n!}{2!*(n-2)!} a^{n-2}b^2=C_n^2a^{n-2}b^2.\\\\k=n\\\frac{n!}{n!*(n-n)!} a^{n-n}b^n=C_n^na^0b^n=C_n^nb^n.\\\\C_n^0a^n+C_n^1a^{n-1}b^1+C_n^2a^{n-2}b^2+...+C_n^nb^n=(a+b)^n.$

$\displaystyle\\(2x+2)^6=\frac{6!}{(6-0)!*0!} (2x)^62^0+\frac{6!}{(6-1)!*1!} (2x)^{6-1}2^1+\frac{6!}{(6-2)!*2!}(2x)^{6-2}2^2+\\\\ +\frac{6!}{(6-3)!*3!} (2a)^{6-3}2^3+\frac{6!}{(6-4)*4!} (2x)^{6-4}b^4+\frac{6!}{(6-5)!*5!}(2x)^{6-5} b^5+\frac{6!}{(6-6)!*6!}(2x)^{6-6}b^6. \\\\$

$(2x+2)^6=\frac{6!}{6!*1} 2^6*x^6*1+\frac{5!*6}{5!*1}2^5*x^5*2+\\\\+\frac{4!*5*6}{4!*1*2}2^4*x^4*2^2+ \frac{3!*4*5*6}{3!*1*2*3} 2^3*x^3*2^3+\frac{4!*5*6}{2!*4!}2^2*x^2*2^4+\\\\+\frac{5!*6}{1!*5!} 2^1*x^1*2^5+\frac{6!}{0!*6!} x^02^6\\\\(2x+2)^6=64x^6+384x^5+960x^4+1280x^3+960x^2+384x+64.$

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1 year ago

PLS HELP I DONT UNDERSTAND :( WILL GIVE BRAINLIEST!! +25 POINTS AHHHH

guajiro [1.7K]

Answer:

the anwser is A

Step-by-step explanation:

i understand

very well and i just took that lesson

4 0

3 years ago

Can someone please help me

Umnica [9.8K]

9514 1404 393

Answer:

central: XWR, VWU
inscribed: VST

Step-by-step explanation:

Point W is the center of the circle. Any angle with W as its vertex is a central angle:

angles XWR and VWU are central angles

Any angle with its vertex on the circle and rays that intersect the circle is an inscribed angle.

angle VST is an inscribed angle

7 0

2 years ago

What ja the slope intercept form of (-6,-3) and (-9,-2)

Y_Kistochka [10]

In order to find the slope intercept form of the given coordinates above (-6,-3)(-9,-2) then you need to use the point slope formula :y-y1=m(x-x1) .now allyou have to due is to label each of the given coordinates x1,y1 and x2 ,y2.This will help with the differentiation of the given coordinates.Once you have done this apply the info within the formula ,and you will get an answer of :y= -1/3x - 5 ,and of course your slope is -1/3 and the y-intercept is -5 .

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3 years ago