I assume that the length of the rectangle is 8 inch more than width .
Lines CE and AD intersect at point B. 37° What is the measure of angle DBE? 370 530 O 1270 0 1430
2 answers:
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Answer:
The width of the frame is 0.0746 meters
Step-by-step explanation:
We are told that after the frame has been attached to the solar collector, the area that is left exposed is . As we see in the figure, the dimensions of this area are
and
where is the width of the frame.
The product of these dimensions must equal the exposed area:
Now since and
we have:
we expand this and solve for x using the quadratic formula:
we get two solutions:
We take the second solution i.e , because first one gives a width larger than the dimensions of the solar collector which cannot be possible.
Thus the width of the frame is 0.0746 meters.
