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Schach [20]
2 years ago
13

In ABC, c=66,m∠A=3230', and m∠C=11140'. Find the length of side a to the nearest tenth.

Mathematics
1 answer:
N76 [4]2 years ago
8 0
Y
=
−
2
x
+
5
y
=
-
2
x
+
5
Use the slope-intercept form to find the slope and y-intercept.
Tap for more steps...
Slope:
−
2
-
2
y-intercept:
(
0
,
5
)
(
0
,
5
)
Any line can be graphed using two points. Select two
x
x
values, and plug them into the equation to find the corresponding
y
y
values.
Tap for more steps...
x
y
0
5
5
2
0
You might be interested in
Find the value of x in the triangle shown below.<br> Choose 1 answer:
Ad libitum [116K]

For the triangle, x is 12 units long.

Step-by-step explanation:

Step 1:

According to the Pythagorean theorem, the square of the hypotenuse is equal to the sum of the squares of the other two sides.

The hypotenuse is the side which is the longest in the triangle and is always opposite the right angle.

In the given triangle, the hypotenuse is 13 units long. The other two sides measure 5 units and x units.

Step 2:

By substituting the known values, we get

13^{2} = 5^{2} + x^{2} .

x^{2} = 169 - 25 = 144.

x = 12.

Rounding this off to the nearest hundred, we get that x is 12 units long.

7 0
3 years ago
Which ordered pair is the solution to the system of equations? {y=3x−102x+3y=3
uysha [10]
(3,-1) for sure i took the test 100% 
hope i helped out 
8 0
3 years ago
Sylvie is going on vacation. She has already driven 58 miles in one hour. If she then travels for 6 hours at an average speed of
Vlada [557]

The answer would be 360 miles

8 0
3 years ago
Which compound inequality could be represented by the graph? -5 4 -3 -1 0 4 0 X5 3 or x&gt;-1​
AveGali [126]

_44_3_10 4 0 ×53 ×<9 =02947</245

8 0
3 years ago
PLEASE HELP , TRYING TO BE ON HONOR ROLL !
borishaifa [10]

Option A

The solution is (0, \frac{-1}{4})

<em><u>Solution:</u></em>

<em><u>Given system of equations are:</u></em>

3x + 6y = 1 ------ eqn 1

x - 4y = 1 ------ eqn 2

We have to find solution to system of equations

We can use substitution method

From eqn 2,

x = 1 + 4y -------- eqn 3

Substitute eqn 3 in eqn 1

3(1 + 4y) + 6y = 1

3 + 12y + 6y = 1

18y = 1 - 3

18y = -2

Divide both sides by 18

y = \frac{-2}{18}\\\\y = \frac{-1}{4}

Substitute the above value of y in eqn 3

x = 1 + 4 \times \frac{-1}{4}\\\\x = 1-1\\\\x = 0

Thus solution is (0, \frac{-1}{4})

8 0
3 years ago
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