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3 years ago

In the expression 3x+7-9n+12, there are how many terms? *

Mathematics

2 answers:

borishaifa [10]3 years ago

8 0

4 terms jekekeowowpm sms,wlwpw

azamat3 years ago

6 0

There are four terms in that expression.

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Graph the line that passes through the points (4,-6) and (-4,-8) and determine the equation of the line.

allochka39001 [22]

Answer:

y=1/4x-7; can't put graph on here

Step-by-step explanation:

m=y2-y1/x2-x1

m=-8+6/-4-4=-2/-8=1/4

put it in point-slope form with (4,-6) as the base

y-y1=m(x-x1)

y+6=1/4(x-4)

y+6=1/4x-1

y=1/4x-7

7 0

3 years ago

2x^2 +7x +3÷x^3 - x^2 +3x-10

krek1111 [17]

You’re welcome slime

3 0

3 years ago

KENNY IS ALLOWED TO WATCH UP TO FIVE HOURS OF TV A WEEK. WRITE AN INEQUALITY THAT SHOWS THE NUMBER OF HOURS KENNY CAN WATCH TV.

Agata [3.3K]

H = hours, so h is less than or equal to 5.

6 0

3 years ago

Read 2 more answers

Problem 10: A tank initially contains a solution of 10 pounds of salt in 60 gallons of water. Water with 1/2 pound of salt per g

AysviL [449]

Answer:

The quantity of salt at time t is $m_{salt} = (60)\cdot (30 - 29.833\cdot e^{-\frac{t}{10} })$ , where t is measured in minutes.

Step-by-step explanation:

The law of mass conservation for control volume indicates that:

$\dot m_{in} - \dot m_{out} = \left(\frac{dm}{dt} \right)_{CV}$

Where mass flow is the product of salt concentration and water volume flow.

The model of the tank according to the statement is:

$(0.5\,\frac{pd}{gal} )\cdot \left(6\,\frac{gal}{min} \right) - c\cdot \left(6\,\frac{gal}{min} \right) = V\cdot \frac{dc}{dt}$

Where:

$c$ - The salt concentration in the tank, as well at the exit of the tank, measured in $\frac{pd}{gal}$ .

$\frac{dc}{dt}$ - Concentration rate of change in the tank, measured in $\frac{pd}{min}$ .

$V$ - Volume of the tank, measured in gallons.

The following first-order linear non-homogeneous differential equation is found:

$V \cdot \frac{dc}{dt} + 6\cdot c = 3$

$60\cdot \frac{dc}{dt} + 6\cdot c = 3$

$\frac{dc}{dt} + \frac{1}{10}\cdot c = 3$

This equation is solved as follows:

$e^{\frac{t}{10} }\cdot \left(\frac{dc}{dt} +\frac{1}{10} \cdot c \right) = 3 \cdot e^{\frac{t}{10} }$

$\frac{d}{dt}\left(e^{\frac{t}{10}}\cdot c\right) = 3\cdot e^{\frac{t}{10} }$

$e^{\frac{t}{10} }\cdot c = 3 \cdot \int {e^{\frac{t}{10} }} \, dt$

$e^{\frac{t}{10} }\cdot c = 30\cdot e^{\frac{t}{10} } + C$

$c = 30 + C\cdot e^{-\frac{t}{10} }$

The initial concentration in the tank is:

$c_{o} = \frac{10\,pd}{60\,gal}$

$c_{o} = 0.167\,\frac{pd}{gal}$

Now, the integration constant is:

$0.167 = 30 + C$

$C = -29.833$

The solution of the differential equation is:

$c(t) = 30 - 29.833\cdot e^{-\frac{t}{10} }$

Now, the quantity of salt at time t is:

$m_{salt} = V_{tank}\cdot c(t)$

$m_{salt} = (60)\cdot (30 - 29.833\cdot e^{-\frac{t}{10} })$

Where t is measured in minutes.

7 0

3 years ago

The median is 28; 16,24,x,48

Nookie1986 [14]

x = 32

To find the media, you take the middle number. If there is no discrete middle number, take the sum of the two closest to the middle and divide by 2.

(24 + x)/2 = 28

Multiply by 2 on both sides to get:

24 + x = 56

Subtract 24 from both sides to isolate the variable:

x = 56 - 24
x = 32

3 0

3 years ago

In the expression 3x+7-9n+12, there are how many terms? *​

In the expression 3x+7-9n+12, there are how many terms? *