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motikmotik
3 years ago
8

How many times greater is the value of the 5 in 503 than the value of the 5 in 53?

Mathematics
2 answers:
oksian1 [2.3K]3 years ago
8 0

Answer:

10 times greater

Step-by-step explanation:

the value of 5 in 503 is 5*100

the value of 5 in 53 is 5*10

So, the value of 5 in 503 is 10 times greater than the value of 5 in 53

disa [49]3 years ago
7 0

Answer:

10 times greater

Step-by-step explanation:

Because value of 5 in 503 is 5*100

Then the value of 5 in 53 is 5*10

So then value of 5 in 503 is 10 times greater than the value of 5 in 53

I hope this helps

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mario62 [17]
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4 0
3 years ago
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Which expression uses the commutative property to make it easier to evaluate 1/6 • 5/7 • 18?
Korvikt [17]
It’s A, Because if you do KCF (Keep Change Flip) It would be 1/6 X 7/5.
8 0
2 years ago
Espana
marysya [2.9K]
First, subtract to get the difference.
2.85 – 2.78 = 0.07

Next, divide 2.78 by 100
2.78 ÷ 100 = 0.0278
So, 0.0278 is 1%. Divide 0.07 by 0.0278 to get the answer.
0.07 ÷ 0.0278 ≈ 2.518
2.518 ≈2.5
Therefore, the percentage increase is approximately 2.5% (that's the answer).

Hope this helps!
8 0
3 years ago
A car's wheels spins at 1000 revolutions per minute. The diameter of the wheels is 23 inches. You want to know how fast the car
ch4aika [34]

Answer:

72,220 inches per  minute

Step-by-step explanation:

A car's wheels spins at 1000 revolutions per minute. The diameter of the wheels is 23 inches.

1 revolution = 2\pi radians

\frac{theta}{tome}=\frac{1000 \ revolution}{1 \ minuite} = \frac{1000* 2\pi }{1} =\frac{2000\pi}{1 \ minute}

Speed V= \frac{r*theta}{t}

r is the radius , theta is the angle and t is the time

We know diameter = 23  , then radius = 23/2

Speed V= \frac{23}{2}*\frac{2000\pi}{1}

Value of pi = 3.14

speed = 23000* 3.14= 72220 inches/ minute


3 0
3 years ago
Read 2 more answers
What is that product of 2x + y and 5x -y + 3
poizon [28]

Answer:

10x² + 6x + 3xy + 3y - y²

Step-by-step explanation:

Each term in the second factor is multiplied by each term in the first factor, as shown

(2x + y)(5x - y + 3)

= 2x(5x - y + 3) + y(5x - y + 3) ← distributing

= 10x² - 2xy + 6x + 5xy - y² + 3y ( collect like terms )

= 10x² + 6x + 3xy + 3y - y²


7 0
2 years ago
Read 2 more answers
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