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LUCKY_DIMON [66]
3 years ago
14

What is 2x^2-x-15 in vertex form

Mathematics
2 answers:
In-s [12.5K]3 years ago
5 0

Answer:

(1/4,-121/8)

Step-by-step explanation:

MaRussiya [10]3 years ago
4 0
Not sure
Someone please help me
I am stuck on this!!!
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You need to put your reindeer, Lancer, Prancer, Gloopin, and Bloopin, in a single-file line to pull your sleigh. However, Prance
marysya [2.9K]

Answer:

P43=4!(4–3)!=241=24

Step-by-step explanation:

There are four choices you can make for the lead reindeer. For each possible choice, there are then three remaining you can choose to fly second, making 4×3=12 choices for the lead pair. For each possible choice there are two remaining reindeer to take up the back position, making 12×2=24 choices for the team of three.

This type of problem is called a permutation problem, and we write Pnr for the number of ways of choosing r items from n possibilities when the order of the items matters. In this case we are choosing 3 reindeer from 4 possibilities, and the order they appear in the flying line does matter, so the answer we want is P43. The general formula is Pnr=n!(n−r)!. For the answer we are looking for we therefore have:

P43=4!(4–3)!=241=24

8 0
3 years ago
Read 2 more answers
Which of the following equations is the equation 2 - 3y + 6x = 0 written in slope-intercept form?
IgorLugansk [536]
The answer us c
..........
7 0
4 years ago
Read 2 more answers
The factors of the number 56 are 1, 2, 4, 7, 8, 14, 28, and 56. Choose the factor pairs of the number 56.
natima [27]

Answer:

b) 7×8

c) 4×14

d) 2×28

Step-by-step explanation:

A factor pair of a number is a pair of numbers that, when multiplied will result in the given number.

The factors of 56 are: 1, 2, 4, 7, 8, 14, 28, and 56.

The factor pairs are:

  • 1 X 56
  • 2 X 28
  • 4 X 14
  • 7 X 8

Out of the options, only Option A is not a factor pair.

8 0
3 years ago
Find the Y-coordinate of point P that lies 1/3 along segment RS, where R (-7, -2) and S (2, 4).
QveST [7]

Solution:

Given that the point P lies 1/3 along the segment RS as shown below:

To find the y coordinate of the point P, since the point P lies on 1/3 along the segment RS, we have

\begin{gathered} RP:PS \\ \Rightarrow\frac{1}{3}:\frac{2}{3} \\ thus,\text{ we have} \\ 1:2 \end{gathered}

Using the section formula expressed as

[\frac{mx_2+nx_1}{m+n},\frac{my_2+ny_1}{m+n}]

In this case,

\begin{gathered} m=1 \\ n=2 \end{gathered}

where

\begin{gathered} x_1=-7 \\ y_1=-2 \\ x_2=2 \\ y_2=4 \end{gathered}

Thus, by substitution, we have

\begin{gathered} [\frac{1(2)+2(-7)}{1+2},\frac{1(4)+2(-2)}{1+2}] \\ \Rightarrow[\frac{2-14}{3},\frac{4-4}{3}] \\ =[-4,\text{ 0\rbrack} \end{gathered}

Hence, the y-coordinate of the point P is

0

8 0
2 years ago
Find the equation of the line that is parallel to the line <img src="https://tex.z-dn.net/?f=y%20%3D%20-%5Cfrac%7B3%7D%7B2%7Dx%2
ivann1987 [24]

A line parallel to your equation has the same slope, so it should be in the form:


y = (-3/2)x + b


To figure what "b" has to be, plug in the point (4,0) and solve:

0 = (-3/2)*4 + b

0 = -6 + b

6 = b

So the equation of the line is:

y = (-3/2)x + 6

3 0
3 years ago
Read 2 more answers
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