Answer:
the answer is 0.84
Step-by-step explanation:
Isolate the variable by dividing each side by factors that don't contain the variable.
y = 2 − x
Given equation is
In general solution of
is
and
So the solution of given equation is
and
Now difference between them is 30.
So we can write
On squaring both side
Take the common out of both numerator and denominator and cancel out the terms which are equal.
(8x³ - 2x² - 3x)/(12x²- 9x)
= x(8x² - 2x -3)/3x(4x - 3)
= (8x² - 2x -3)/3(4x - 3)
=(4x-3)(2x+1)/3(4x-3)
= (2x+1)/3
Answer:
1) $4400
2) $4400
Step-by-step explanation:
Let
X = price in first year
Y = price in 2nd year
Z = price in 3rd year
A = price in the end of 3rd year
Y = 1.1 X
Z = 0.8 Y
substitute Y into Z get Z = 0.88 X
A = 1.25 Z= 1.25(0.88X) = 1.1 X
1)
(125/100) Z = 22000
Z = 22000 x 100 / 125 = 17600
Z = 0.8Y
Y = Z/0.8 = 1.25Z
Amount of dollar decrease in 2nd year = Y - Z
= 1.25Z - Z = 0.25Z = 0.25 x 17600 = 4400 dollar
2)
Decrease in price over first 2 years = Increase in property in 3rd year - 2000
Hence, X - Z = (A-Z) - 2000
X - 0.8X = 1.1 X - 0.88 X - 2000
X - 0.88X - 1.1X + 088X = -2000
-0.1 X = -2000
0.1 X = 2000
X = 20000
Amount of dollar decrease during 2nd year = Y - Z = 1.1X - 0.88X = 0.22X
= (0.22) x (20000) = 4400 dollars
