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SOVA2 [1]
3 years ago
12

There are five kids at the park with pieces of candy. Sara has fourteen pieces, Jon has seventeen pieces, Sam has eight pieces,

Dave has nineteen pieces and Allie has seven pieces. What is the mean absolute deviation of this data
Mathematics
1 answer:
MakcuM [25]3 years ago
4 0

Answer:

13

Step-by-step explanation:

The mean is the average of the data points.

(14 + 17 + 8 + 19 + 7) ÷ 5 = 65 ÷ 5 = 13

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After distributing, which equation is equivalent to -4(3x + 2) = 10a.-12x -8 = 10b.-12x + 8 = 10c.-12x -6 = 10d.-12x + 6 = 1
rodikova [14]

Answer:

Option A: -12x-8=10 is the correct answer.

Step-by-step explanation:

Given equation is:

-4 (3x+2) = 10

We will distribute the equation by multiplying the terms inside the brackets with -4.

Therefore,

-4*3x + 2*-4 = 10

-12x +(-8) = 10

-12x - 8 = 10

The equation -4 (3x+2) = 10 will become -12x-8=10 after distributing.

Hence,

Option A: -12x-8=10 is the correct answer.

5 0
3 years ago
WILL MARK BRAINLIEST ONLY HAVE 10 MINUTES
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Answer:

A

Step-by-step explanation:

6 0
3 years ago
Solve each expression.reduce to simplest form of 5/8x4/5
Butoxors [25]
5/8 * 4/5
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4 0
3 years ago
Read 2 more answers
A sports teacher had 1025 sweets. After distributing these equally amongst all the participants in a sports meet, he had just 1
Cerrena [4.2K]

Step-by-step explanation:

Since it remains only 1 sweet, we can subtract it from the total and get the amount of sweets distributed (=1024).

As all the sweets are distributed equally, we must divide the number of distributed sweets by all its dividers (excluding 1024 and 1, we'll see later why):

1) 512 => 2 partecipants

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The number on the left represents the number of sweets given to the partecipants, and on the right we have the number of the partecipants. Note that all the numbers on the left are dividers of 1024.

Why excluding 1 and 1024? Because the problem tells us that there remains 1 sweet. If there was 1 sweet for every partecipant, the number of partecipants would be 1025, but that's not possible as there remains 1 sweet. If it was 1024, it wouldn't work as well because the sweets are 1025 and if 1 is not distributed it goes again against the problem that says all sweets are equally distributed.

5 0
3 years ago
i know this is a lot of questions but im really bad at math and i keep getting a 50% on my test and this is my last chance to pa
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Answer:

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