-29664 is the correct answer. This mostly deals with the zeros and crossing them off
Answer:
4?
Step-by-step explanation:
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The missing expression should be for Step 3 is [(25 + 3)/0.5] - 16.4 ÷ 4 and the missing expression should be for Step 6 is 56 - 4.1
<h3>Part A: Explain what the missing expression should be for Step 3</h3>
To do this, we make use of the expression in step 2
The expression in step 2 is
[(5^2 + 3)/0.5] - 16.4 ÷ 4
The next step at this stage is to evaluate the expression 5^2
So, we have:
[(25 + 3)/0.5] - 16.4 ÷ 4
Hence, the missing expression should be for Step 3 is [(25 + 3)/0.5] - 16.4 ÷ 4
<h3>Part B: Explain what the missing expression should be for Step 6.</h3>
To do this, we make use of the expression in step 5
The expression in step 5 is
56 - 16.4 ÷ 4
The next step at this stage is to evaluate the expression 16.4 ÷ 4
So, we have:
56 - 4.1
Hence, the missing expression should be for Step 6 is 56 - 4.1
Read more about expressions at:
brainly.com/question/723406
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The
<u>correct diagram</u> is attached.
Explanation:
Using technology (such as Geogebra), first construct a line segment. Name the endpoints C and D.
Construct the perpendicular bisector of this segment. Label the intersection point with CD as B, and create another point A above it.
Measure the distance from C to B and from B to D. They will be the same.
Measure the distance from A to B. If it is not the same as that from C to B, slide A along line AB until the distance is the same.
Using a compass and straightedge:
First construct segment CD, being sure to label the endpoints.
Set your compass a little more than halfway from C to D. With your compass set on C, draw an arc above segment CD.
With your compass set on D (the same distance as before) draw an arc above segment CD to intersect your first arc. Mark this intersection point as E.
Connect E to CD using a straightedge; mark the intersection point as B.
Set your compass the distance from C to B. With your compass on B, mark an arc on EB. Mark this intersection point as A.
AB will be the same distance as CB and BD.