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rodikova [14]
4 years ago
5

The volleyball team at West View High School is comparing T-shirt companies where they can purchase their practice shirts. The t

wo companies, Shirt Box and Just Tees, are represented by this system of equations where x is the number of T-shirts and y is the total cost of the T-shirts.
y = 10.5x

y = 7.5x + 30

How many T-shirts would the volleyball team need to purchase from each company for the total cost to be equal?

For the total cost to be the same for both companies, the volleyball team would need to purchase____ T-shirts from each company for a total of $____for each company.
Mathematics
2 answers:
Alex73 [517]4 years ago
8 0

Answer:

Q#1.total number of T-shirts for  total cost to be equal=10

Q#2.For the total cost to be the same for both companies, the volleyball team would need to purchase 10 T-shirts from each company

Q#3.total of $105 for each company.


Step-by-step explanation:

Q#1

two functions are given

y=10.5x

y=7.5x+30

where y represents cost and x represents number of shirts

we have to find number of shirts to be purchased from each company keeping cost equal

hence we will write

10.5x=7.5x+30

10.5x-7.5x=30

3x=30

x=30/3

x=10

Number of shirts to be equal cost price is 10

Q#2

two functions are given

y=10.5x

y=7.5x+30

where y represents cost and x represents number of shirts

we have to find number of shirts to be purchased from each company keeping cost equal

hence we will write

10.5x=7.5x+30

10.5x-7.5x=30

3x=30

x=30/3

Number of shirts =x=10

Q#3

total cost=y=?

for y=10.5x

put x=10

y=10.5*10

cost=y=105

and for other function

for y=7.5x+30

put x=10

y=7.5(10)+30

y=75+30=105

slega [8]4 years ago
6 0

Answer:

1) 10

2) 105

Step-by-step explanation:

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Firlakuza [10]

Answer:

The mean and standard deviation changed to 23.5 and 14.62 respectively, based on all 12 samples.

Step-by-step explanation:

We are given that the Six samples are collected of the number of scanning errors: 36, 14, 21, 39, 11, and 2 errors, per 1,000 scans each.

Representing the data in tabular form;

           X                            X - \bar X                            (X - \bar X)^{2}

          36                     36 - 20.5 = 15.5                   240.25

          14                      14 - 20.5 = -6.5                     42.25  

          21                       21 - 20.5 = 0.5                      0.25

          39                      39 - 20.5 = 18.5                   342.25

           11                        11 - 20.5 = -9.5                     90.25

           2                         2 - 20.5 = -18.5               <u>    342.25    </u>

        Total                                                              <u>   1057.5      </u>

Now, the mean of these value is given by;

        Mean, \bar X  =  \frac{\sum X}{n}

                         =  \frac{36+14+21+39+11+2}{6}

                         =  \frac{123}{6}  =  20.5

Standard deviation formula for discrete distribution is given by;

           Standard deviation, \sigma  =  \sqrt{\frac{\sum (X -\bar X)^{2} }{n-1} }

                                                 =  \sqrt{\frac{1057.5 }{6-1} } = 14.54

Now, the manager has six more samples taken:

33, 45, 34, 17, 1, and 29 errors, per 1,000 scans each

So, the modified table would be;

           X                            X - \bar X                            (X - \bar X)^{2}

          36                     36 - 23.5 = 12.5                   156.25

          14                      14 - 23.5 = -9.5                     90.25  

          21                       21 - 23.5 = -2.5                     6.25

          39                      39 - 23.5 = 15.5                   240.25

           11                        11 - 23.5 = -12.5                   156.25

           2                         2 - 23.5 = -21.5                   462.25    

          33                       33 - 23.5 = 9.5                     90.25

         45                        45 - 23.5 = 21.5                   462.25

         34                        34 - 23.5 = 10.5                   110.25

          17                         17 - 23.5 = -6.5                    42.25

           1                           1 - 23.5 = -22.5                   506.25

          29                        29 - 23.5 = 5.5               <u>     30.25      </u>

        Total                                                              <u>      2353      </u>

<u />

Now, the mean of these value is given by;

        Mean, \bar X  =  \frac{\sum X}{n}

                         =  \frac{36+14+21+39+11+2+33+45+34+17+1+29}{12}

                         =  \frac{282}{12}  =  23.5

Standard deviation formula for discrete distribution is given by;

           Standard deviation, \sigma  =  \sqrt{\frac{\sum (X -\bar X)^{2} }{n-1} }

                                                 =  \sqrt{\frac{2353 }{12-1} } = 14.62

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