Answer:
The diagonal is 39.54 in
The baton will fit in the box if it is placed in the direction of the diagonal of the cube since:
39.54 inches > 38 inches
Step-by-step explanation:
The range of function is { 0, -6, -9}
<h3><u>Solution:</u></h3>
Given that the function is:

Also given its domain is (-8, 0, 4)
<em><u>To find: Range of the function</u></em>
Domain of the function is possible input of the function that is "x" and range of the function is possible output of the function that is f(x)
As there are only three input values for "x" that are (-8, 0, 4) we can determine the range by calculating value of f(x) for each of the x
<em><u>For x = 8:</u></em>


<em><u>For x = 0:</u></em>

<em><u>For x = 4:</u></em>

Thus the range of function is { 0, -6, -9}
Solutions
Probability: number of favourable outcomes
__________________________
total number of possible outcomes
In general, the total number of possible outcomes can be determined
by multiplying the number of possible outcomes for each event.
P(A|B)=
P(A|B) ⇒<span> P(taking history | taking science) , Therefore A corresponds to taking history, B corresponds to taking science.
</span>
<span>P(A,B) will be the probability that a student is taking both of the subjects.
</span>
<span>P(B) is the probability that a student is taking the subject science (regardless of whether he/she takes history or not)</span>
Now to solve the problem you plug in the given numbers.
0.48 ÷ 0.82
<span>0.48 is the Probability of (A,B) and 0.82 is the Probability of (B)
</span>
= 0.585<span>37
Rounded to 0.59
Answer = (D) </span>
Answer:
C = 38n + 1750; 15,050
Step-by-step explanation:
We know that for <em>each </em>person, there's a fee of 38. That signifies that the n will be after 38. 1,750 is a one-time fee, so that's by itself. Plug it into the equation to get your first answer. Now, solve for b) by writing C = 38(350) + 1750; C = 15,050
Answer:
- cos(2Ф) = cos²(Ф) -sin²(Ф)
- cos(2Ф) = 1 -2sin²(Ф)
- cos(2Ф) = 2cos²(Ф) -1
Step-by-step explanation:
The angle sum formula for cosine is ...
cos(α+β) = cos(α)cos(β) -sin(α)sin(β)
When we have α = β = Ф, this becomes ...
cos(Ф+Ф) = cos(Ф)cos(Ф) -sin(Ф)sin(Ф)
cos(2Ф) = cos²(Ф) -sin²(Ф)
The "Pythagorean identity" can be used to write this in terms of sine or cosine.
cos(2Ф) = (1 -sin²(Ф)) -sin²(Ф)
cos(2Ф) = 1 -2sin²(Ф)
or
cos(2Ф) = cos²(Ф) -(1 -cos²(Ф))
cos(2Ф) = 2cos²(Ф) -1