Question

1)X²+5X-50=02)6²+6B-16=03)R²+6R+8=04)P²+5P+6=0​

Answer 1

Factorise :

$\\ 1) \sf \: \: x² + 5x - 50 = 0 \: \: \: \: \: \: \: \: \: \: \: \\ \\ \implies \sf \: {x}^{2} + 10x - 5x - 50 = 0 \\ \\ \sf \: \implies x(x + 10) - 5(x + 10) = 0 \\ \\ \sf \implies \: (x - 5)(x + 10) = 0 \: \: \: \: \: \: \:$

Whether,

• x = 5
• x = -10

$\\ \\ \sf 2) \: b²+6b-16=0 \: \: \: \: \: \: \: \\ \\ \sf \: \implies {b}^{2} + 8b - 2b - 16 = 0 \: \: \: \\ \\ \sf \: \implies b(b + 8) - 2(b + 8) = 0 \\ \\ \sf \: \implies (b - 2)(b + 8) = 0 \: \: \: \: \: \: \: \: \: \:$

Whether,

• b = 2
• b = -8

$\\ \\ 3) \: \sf \: r²+6r+8=0 \: \: \: \: \: \: \: \: \: \\ \\ \sf \implies {r}^{2} + 2r + 4r + 8 = 0 \: \: \: \\ \\ \sf \: \implies r(r + 2) + 4(r + 2) = 0 \\ \\ \sf \: \implies (r + 2)(r + 4) = 0 \: \: \: \: \: \: \: \:$

Whether,

• r = -2
• r = -4

$\\ \\ 4) \sf\: \: p²+5p+6=0 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \sf \: \implies {p}^{2} + 2p + 3p + 6 = 0 \: \: \: \: \: \: \: \: \: \\ \\ \implies\sf \: p(p + 2) + 3(p + 2) = 0 \\ \\ \implies \sf \: (p + 2)(p + 3) = 0 \: \: \: \: \: \: \: \:$

Whether,

• p = -2
• p = -3

Answer 2

1) X²+5X-50=0

↠X² + 10X -5X -50 = 0

↠X(X+10)-5(X+10) = 0

↠(X-5)(X+10)=0

↠X = 5, -10

2)B²+6B-16=0

↠B² + 8B - 2B -16 = 0

↠B(B+8) -2(B+8) =0

↠(B-2) (B+8) =0

↠B = 2,-8

3)R²+6R+8=0

↠R²+4R+2R+8=0

↠R(R+4)+2(R+4)=0

↠(R+2)(R+4)=0

↠R=-2,-4

4) P²+5P+6=0

↠P²+3P+2P+6=0

↠P(P+3)+2(P+3)=0

↠(P+2)(P+3)=0

↠P=-2,-3