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3 years ago

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Ricardo’s recipe for four loaves of bread requires 2/3 cup of olive oil he only wants to make one loaf Ricardo makes a model to

find out how much Ol Ricardo‘s recipe for four loaves of bread requires 2/3 cup of olive oil he only wants to make one loaf Ricardo makes a model to find out how much our oil He needs to use he fold a piece of paper into three parts and shades two parts then you fold the paper into four parts and shades 1/4 of the shaded part Riccardo decides he needs 1/4 cup of olive oil is he right.

1 answer:

viktelen [127]3 years ago

5 0

He isn't right. He needs 1/6 cup of olive oil since 2/3 times 1/4 = 1/6

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What steps should be taken to calculate the volume of the prism? Select three options. A rectangular prism with a length of 9 an

fgiga [73]

The steps to be taken to determine the volume of the rectangular prism are:

Use A = bh to find the area of the base.

Use V = Bh to find the volume of the prism.

Volume of the prism, V = (228)(6) = 1,368 feet cubed.

<h3>How to Find the Volume of a Rectangular Prism?</h3>

A rectangular prism has a height, base, and width. The volume of the rectangular prism can be found by using the following steps:

Find the base area of the rectangular prism using the formula, A = bh, where b is the base length and h is the height of the base.
Then, find the Volume using the formula, V = Bh, where B is the base area and h is the height of the prism.

Parameters are:

Length of prism = 9 and one-half feet,

Width of prism = 24 feet,

Height of prism = 6 feet

Given the dimensions of the rectangular prism above, do the following:

Find the area of the base of the rectangular prism:

Area of base = (9 1/2)(24) = 228 cm²

Find the Volume of the prism using V = Bh :

Volume of the prism = (228)(6) = 1,368 feet cubed.

Therefore, the steps to be taken to determine the volume of the rectangular prism are:

Use A = bh to find the area of the base.
Use V = Bh to find the volume of the prism.
Volume of the prism, V = (228)(6) = 1,368 feet cubed.

Learn more about volume of the rectangular prism on:

brainly.com/question/12917973

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2 years ago

Find the measures of the missing angles <br><br><br><br> Help pleaseee

kondaur [170]

Answer:

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3 years ago

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How do I prove this problem?

vova2212 [387]

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3 years ago

Solve y ' ' + 4 y = 0 , y ( 0 ) = 2 , y ' ( 0 ) = 2 The resulting oscillation will have Amplitude: Period: If your solution is A

Vlad [161]

Answer:

$y(x)=sin(2x)+2cos(2x)$

Step-by-step explanation:

$y''+4y=0$

This is a homogeneous linear equation. So, assume a solution will be proportional to:

$e^{\lambda x} \\\\for\hspace{3}some\hspace{3}constant\hspace{3}\lambda$

Now, substitute $y(x)=e^{\lambda x}$ into the differential equation:

$\frac{d^2}{dx^2} (e^{\lambda x} ) +4e^{\lambda x} =0$

Using the characteristic equation:

$\lambda ^2 e^{\lambda x} + 4e^{\lambda x} =0$

Factor out $e^{\lambda x}$

$e^{\lambda x}(\lambda ^2 +4) =0$

Where:

$e^{\lambda x} \neq 0\\\\for\hspace{3}any\hspace{3}\lambda$

Therefore the zeros must come from the polynomial:

$\lambda^2+4 =0$

Solving for $\lambda$ :

$\lambda =\pm2i$

These roots give the next solutions:

$y_1(x)=c_1 e^{2ix} \\\\and\\\\y_2(x)=c_2 e^{-2ix}$

Where $c_1$ and $c_2$ are arbitrary constants. Now, the general solution is the sum of the previous solutions:

$y(x)=c_1 e^{2ix} +c_2 e^{-2ix}$

Using Euler's identity:

$e^{\alpha +i\beta} =e^{\alpha} cos(\beta)+ie^{\alpha} sin(\beta)$

$y(x)=c_1 (cos(2x)+isin(2x))+c_2(cos(2x)-isin(2x))\\\\Regroup\\\\y(x)=(c_1+c_2)cos(2x) +i(c_1-c_2)sin(2x)\\$

Redefine:

$i(c_1-c_2)=c_1\\\\c_1+c_2=c_2$

Since these are arbitrary constants

$y(x)=c_1sin(2x)+c_2cos(2x)$

Now, let's find its derivative in order to find $c_1$ and $c_2$

$y'(x)=2c_1 cos(2x)-2c_2sin(2x)$

Evaluating $y(0)=2$ :

$y(0)=2=c_1sin(0)+c_2cos(0)\\\\2=c_2$

Evaluating $y'(0)=2$ :

$y'(0)=2=2c_1cos(0)-2c_2sin(0)\\\\2=2c_1\\\\c_1=1$

Finally, the solution is given by:

$y(x)=sin(2x)+2cos(2x)$

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3 years ago

Describe the solutions of 2-5>n in words

inna [77]

$2-5\ \textgreater \ n \ \textgreater \ Switch\;sides \ \textgreater \ n\ \textless \ 2-5 \ \textgreater \ Simplify \ \textgreater \ 2-5 \ \textgreater \ -3$

$n\ \textless \ -3$

Hope this helps!

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3 years ago