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3 years ago

Which is equivalent to the complex number i^32?

Mathematics

1 answer:

Ksivusya [100]3 years ago

4 0

Answer:

where i^2 = -1 (minus one)

So, i^2 = -1

i^4 = (i^2)^2 = (-1)^2 = -1 X-1 = 1

like ;

i^32 = (i^2)^16 = (-1)^16 = -1 X -1 X-1 X -1 X-1 X -1 X-1 X -1 X-1 X -1 X-1 X -1 X-1 X -1 X-1 X -1 X

= 1

Step-by-step explanation:

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