Question

Which is equivalent to the complex number i^32?

Answer 1

Answer:

where i^2 = -1 (minus one)

So, i^2 = -1

i^4 = (i^2)^2 = (-1)^2 = -1 X-1 = 1

like ;

i^32 = (i^2)^16 = (-1)^16 =  -1 X -1 X-1 X -1 X-1 X -1 X-1 X -1 X-1 X -1 X-1 X -1 X-1 X -1 X-1 X -1 X

     = 1

Step-by-step explanation: