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2 years ago

6

Pls help, i will give someone a brainlest! Options: Kayla joshua

2 answers:

Genrish500 [490]2 years ago

7 0

Answer:

Kayla would be correct in this problem

AleksAgata [21]2 years ago

4 0

Answer:

Kayla

Step-by-step explanation:

A slope of 0 is a horizontal line

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Forty- two people attended s meeting about a zoning ordinance. Six more of the attendees voted in favor of the ordinance than th

kumpel [21]

Let the attendees in opposition be x. This means that the attendees in favour are x+6.
That means x+x+6=42, which is 2x+6=42, so 2x=36 and x=18. Therefore, there are 18 attendees who opposed it.

3 0

2 years ago

Y=-x^2-x-3 find the X intercept for The parabola define by this equation

KengaRu [80]

To find the X intercept make y =0. Then factor out a negative on the side with the equation for each of the terms, so it becomes
0=-(x^2+x+3)
0=(x^2+X+3)
0-3=(x^2+X)
-3=x(X+1)
-3=X, X intercept -3,0
-3=(X+1)
-4=X, X intercept -4,0.
These are possible X intercepts you can check by using quadratic formula as well.

7 0

3 years ago

Find the length x. .

AleksAgata [21]

Answer:

6.5

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Find the first four terms of the sequence given by the following an=57-4(n-1),n=1,2,3

Crazy boy [7]

Answer:

57, 53, 49, 45

Step-by-step explanation:

Substitute for the n for n=1,2,3,4 so the first term is 57-4(1-1) so =57-4(0) so

a(1) = 57-0 = 57 so that is the 1st term

2nd term 57-4(2-1) so =57-4(1) so a(2) = 57-4 = 53, etc.

4 0

2 years ago

[30 POINTS] Please help!!!

Len [333]

Answer:

Part 1) $y=1.5x+5$

Part 2) $y=-(2/3)x-(11/3)$

Part 3) $y=0.25x+2.75$

Part 4) $y=-2x+5$

Part 5) $y=0.5x-1$

Part 6) The graph in the attached figure

Step-by-step explanation:

Part 1) we have

$m=3/2=1.5$

$point(-2,2)$

The equation of the line into point slope form is equal to

$y-y1=m(x-x1)$

substitute

$y-2=1.5(x+2)$

$y=1.5x+3+2$

$y=1.5x+5$

Part 2) we know that

If two lines are perpendicular

then

the product of their slopes is equal to minus one

so

$m1*m2=-1$

the slope of the line 1 is equal to

$m1=1.5$

Find the slope m2

$1.5*m2=-1$

$m2=-2/3$

Find the equation of the line 2

we have

$m2=-2/3$

$point(-7,1)$

The equation of the line into point slope form is equal to

$y-y1=m(x-x1)$

substitute

$y-1=(-2/3)(x+7)$

$y=-(2/3)x-(14/3)+1$

$y=-(2/3)x-(11/3)$

Part 3) we have

$m=1/4=0.25$

$point(1,3)$

The equation of the line into point slope form is equal to

$y-y1=m(x-x1)$

substitute

$y-3=0.25(x-1)$

$y=0.25x-0.25+3$

$y=0.25x+2.75$

Part 4) we have

$m=-2$

$b=5$ -----> y-intercept

we know that

The equation of the line into slope intercept form is equal to

$y=mx+b$

substitute the values

$y=-2x+5$

Part 5) we have that

The slope of the line 4 is equal to $-2$

so

the slope of the line perpendicular to the line 4 is equal to

$-2*m=-1\\m=(1/2)=0.5$

therefore

in this problem we have

$m=0.5$

$point(-2,-2)$

The equation of the line into point slope form is equal to

$y-y1=m(x-x1)$

substitute

$y+2=0.5(x+2)$

$y=0.5x+1-2$

$y=0.5x-1$

Part 6)

using a graphing tool

see the attached figure

3 0

2 years ago