Ur answer is: a-half-inch
Answer:
The answer to this question is given below in the explanation section.
Explanation:
The value stored by a variable can be changed after it is assigned(true).
The value of a variable can be changed after it is assigned, for example:
int a=10;
and we can change the value of variable a in letter program such as:
a=15;
Variables are a name for a spot in the computer's memory (true).
it is true, because the variables value stored in the computer's memory and we can access theses values by their name (variable name). so Variables are a name for a spot in the computer's memory.
Variable names can be words: such as temperature or height (true).
Yes, the variable name can be words such as height, width, temperature etc.
The value stored by a variable cannot be changed after it is assigned (false).
It is noted that the value stored by a variable can be changed after it is assigned. However, it is noted that is some programming language, you can't change the value of static variable.
Answer:
public class Digits
{
public static boolean allDigitsOdd(int num)
{
boolean flag=true;
int rem;
while(num>0)
{
rem=num%10;
num=num/10;
if(rem%2==0) // if a even digit found immediately breaks out of loop
{
flag=false;
break;
}
}
return flag; //returns result
}
public static void main(String args[])
{
System.out.println(allDigitsOdd(1375)); //returns true as all are odd digits
}
}
OUTPUT :
true
Explanation:
Above program has 2 static methods inside a class Digits. Logic behind above function is that a number is divided by 10 until it is less than 0. Each time its remainder by 0 is checked if even immediately breaks out of the loop.
Answer:
retupmoc
Explanation:
1.) Anwser will be retupmoc
because
public static String mysteryString(String s){
if(s.length() == 1){
return s;
}
else{
return s.substring(s.length() -1) + mysteryString(s.substring(0, s.length()-1));
}
}
In this program input is "computer" . So the function mysteryString(String s) it does
return s.substring(s.length() -1) + mysteryString(s.substring(0, s.length()-1));
so when it enters the first time ??s.substring(s.length() -1) and it will be give you 'r' then it calls the function recursively by reducing the string length by one . So next time it calls the mysteryString function with string "compute" and next time it calls return s.substring(s.length()-1)? + mysteryString(s.substring(0,s.length-1)) so this time it gives "e" and calls the function again recursively . It keeps on doing till it matched the base case.
so it returns "retupmoc".
