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3 years ago

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Mathematics

1 answer:

Solnce55 [7]3 years ago

6 0

Answer:

6ft

Step-by-step explanation:

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PLEASE HELP ME!

lawyer [7]

At the beining, he has 76
that is at x=0
y=mx+76

find m
given
when x=2, y=100
find m

100=2m+76
minus 76 both sides
24=2m
divide both sides by 2
12=m

the equatin is

y=12x+76

6 0

3 years ago

A water well rig has dug to a height of -60 feet after one full day of continuous use. if the rig has been running and is curren

Romashka [77]

Given :

A water well rig has dug to a height , H = 60 feet after one full day of continuous use .

To Find :

If the height is currently 143.6 feet how time it been running .

Solution :

It is given that height after 24 hours of use is 60 feet .

So , height loose in 1 hours is :

$h=\dfrac{60}{24}\ feet\\\\h=2.5 \ feet$

Now , time taken to cover a height of 143.6 feet is :

$t = \dfrac{143.6}{2.5}\ hours\\\\t=57.44\ hours$

Therefore , time taken is 57.44 hours .

Hence , this is the required solution .

6 0

3 years ago

The cosine law

romanna [79]

$\bf \textit{Law of sines}
\\ \quad \\
\cfrac{sin(\measuredangle A)}{a}=\cfrac{sin(\measuredangle B)}{b}=\cfrac{sin(\measuredangle C)}{c}\\\\
-------------------------------\\\\$

$\bf \cfrac{sin(88^o)}{39.9}=\cfrac{sin(A)}{31}\implies \cfrac{31\cdot sin(88^o)}{39.9}=sin(A)
\\\\\\
sin^{-1}\left[ \cfrac{31\cdot sin(88^o)}{39.9} \right]=sin^{-1}\left[ sin(A) \right]
\\\\\\
sin^{-1}\left[ \cfrac{31\cdot sin(88^o)}{39.9} \right]=\measuredangle A
\\\\\\
50.93841^o\approx \measuredangle A\qquad thus\qquad \measuredangle C\approx 41.0619^o$

3 0

3 years ago

Combien de morceaux de 15cm peut on découper dans une ficelle de 1cm ?

poizon [28]

Answer:

English translate for my help please??!

Step-by-step explanation:

7 0

3 years ago

The coldest temperature in the city today was 14.8 degrees (Fahrenheit) lower than the hottest temperature. Let H represent the

devlian [24]

<h3>The formula that correctly relates H and L is H = L + 14.8</h3><h3>The high temperature is 83.7 degrees</h3>

<em><u>Solution:</u></em>

Let H represent the high temperature

Let L represent the low temperature

Given that,

<em><u>The coldest temperature in the city today was 14.8 degrees (Fahrenheit) lower than the hottest temperature</u></em>

L = H - 14.8

Rearrange,

H = L + 14.8

<em><u>If the low temperature was 68.9 degrees, what was the high temperature?</u></em>

L = 68.9

Then,

H = 68.9 + 14.8

H = 83.7

Thus the high temperature is 83.7 degrees

6 0

3 years ago