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trapecia [35]
3 years ago
6

Can someone help please ?

Mathematics
1 answer:
vladimir2022 [97]3 years ago
5 0

2. Because it is being reflected across the X axis, the X coordinate would change signs, but the Y coordinate would remain the same sign.

A(-6,-4) would become A'(6,-4)

B(-3,5) would become B'(3,5)

C(1,-1) would become C'(-1,-1)


The answer would be the third choice.


3. Reflected across the Y axis, the X would stay the same sign and the Y would change signs.

P(-2,-4) would become P'(-2,4)

Q(2,-5) would become Q'(2,5)

R(-1,-8) would become R'(-1,8)

The answer would be the second choice.

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Write the equation of the line that passes through the points (2, 1) and (-8,-8).
nordsb [41]

Answer:

y = 0.9x - 0.8

Step-by-step explanation:

First you use the formula m = (y2-y1) / (x2-x1)

Sub in the 2 points you are given and you get m = (-8-1) / (-8-2)

m = -9/-10 = 9/10

Now u use the point slope formula, (y - y1) = m(x - x1)

Sub in the points and you get (y - 1) = 9/10 (x-2)

Expand it out to get y - 1 = 9/10x - 18/10

multiple everything by 10 = 10y - 10 = 9x -18

make y the subject, 10y = 9x - 8

y = 0.9x - 0.8

8 0
3 years ago
Helpppp me plz any help would work :)
mixer [17]

Answer:

2d+3 dollars

Step-by-step explanation:

the second one 2d+3

7 0
3 years ago
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could someone out there perhaps help me? i’m so lost even though it’s probably so simple. i’ll give you brainleist :)
Temka [501]

Answer:

y= -x+7, b= sqrt(2P/a), c=3P^2-b

Step-by-step explanation:

First, make a table regarding both of the equations. You will eventually find out that both lines intersect at the point (2, 5) after you find the points on the table. From there, subtract x from both sides in the equation x + y = 2. You will      get y = -x + 2. Since they said the line was parallel, find a line that has the slope of negative one. Since we know that this line intersects the point in which the first two lines intersect, we know that the y-intercept will be 7. The equation of the line would be y=-x+7.

Multiply both sides by 2. Then, divide both sides by a to get b^2=(2P/a). Take the square root to get the value of b, which is sqrt(2P/a).

Square both sides of the equation to get P^2=(b+c)/3. Cross multiply to get 3P^2=b+c. Subtract b from both sides to get c=3P^2-b.

8 0
3 years ago
Write the equation of the line, in standard form, that passes through the origin and is parallel to x + y = 6. Include your work
asambeis [7]
Ax+by=c
a=1 
b=1
slope= -a/b=-1
y=mx+b
y=-x+b
b=0
x+y=0
8 0
3 years ago
How do you model the square root of 16
kotegsom [21]
\sqrt{16} =\sqrt{4*4}=\sqrt{4}*\sqrt{4}=2*2=4


4 0
3 years ago
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