Can someone help please ?

Mathematics

1 answer:

vladimir2022 [97]4 years ago

5 0

2. Because it is being reflected across the X axis, the X coordinate would change signs, but the Y coordinate would remain the same sign.

A(-6,-4) would become A'(6,-4)

B(-3,5) would become B'(3,5)

C(1,-1) would become C'(-1,-1)

The answer would be the third choice.

3. Reflected across the Y axis, the X would stay the same sign and the Y would change signs.

P(-2,-4) would become P'(-2,4)

Q(2,-5) would become Q'(2,5)

R(-1,-8) would become R'(-1,8)

The answer would be the second choice.

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2y-4x=-12 what is the slope intercept

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The point (1/3,1/4) lies on the terminal said of an angle. Find the exact value of the six trig functions and explain which func

katrin2010 [14]

Answer:

sine and cosec are inverse of each other.

cosine and sec are inverse of each other.

tan and cot are inverse of each other.

Step-by-step explanation:

Given point on terminal side of an angle ( $\frac{1}{3},\frac{1}4$ ).

Kindly refer to the attached image for the diagram of the given point.

Let it be point A( $\frac{1}{3},\frac{1}4$ )

Let O be the origin i.e. (0,0)

Point B will be ( $\frac{1}{3},0$ )

Now, let us consider the right angled triangle $\triangle OBA$ :

Sides:

$Base, OB = \frac{1}{3}\\Perpendicular, AB = \frac{1}{4}$

Using Pythagorean theorem:

$\text{Hypotenuse}^{2} = \text{Base}^{2} + \text{Perpendicular}^{2}\\\Rightarrow OA^{2} = OB^{2} + AB^{2}\\\Rightarrow OA^{2} = \frac{1}{3}^{2} + \frac{1}{4}^{2}\\\Rightarrow OA = \sqrt{\frac{1}{3}^{2} + \frac{1}{4}^{2}}\\\Rightarrow OA = \sqrt{\frac{4^2+3^2}{3^{2}.4^2 }}\\\Rightarrow OA = \frac{5}{12}$